diff --git a/src/HOL/Euclidean_Division.thy b/src/HOL/Euclidean_Division.thy --- a/src/HOL/Euclidean_Division.thy +++ b/src/HOL/Euclidean_Division.thy @@ -1,1981 +1,1981 @@ (* Title: HOL/Euclidean_Division.thy Author: Manuel Eberl, TU Muenchen Author: Florian Haftmann, TU Muenchen *) section \Division in euclidean (semi)rings\ theory Euclidean_Division imports Int Lattices_Big begin subsection \Euclidean (semi)rings with explicit division and remainder\ class euclidean_semiring = semidom_modulo + fixes euclidean_size :: "'a \ nat" assumes size_0 [simp]: "euclidean_size 0 = 0" assumes mod_size_less: "b \ 0 \ euclidean_size (a mod b) < euclidean_size b" assumes size_mult_mono: "b \ 0 \ euclidean_size a \ euclidean_size (a * b)" begin lemma euclidean_size_eq_0_iff [simp]: "euclidean_size b = 0 \ b = 0" proof assume "b = 0" then show "euclidean_size b = 0" by simp next assume "euclidean_size b = 0" show "b = 0" proof (rule ccontr) assume "b \ 0" with mod_size_less have "euclidean_size (b mod b) < euclidean_size b" . with \euclidean_size b = 0\ show False by simp qed qed lemma euclidean_size_greater_0_iff [simp]: "euclidean_size b > 0 \ b \ 0" using euclidean_size_eq_0_iff [symmetric, of b] by safe simp lemma size_mult_mono': "b \ 0 \ euclidean_size a \ euclidean_size (b * a)" by (subst mult.commute) (rule size_mult_mono) lemma dvd_euclidean_size_eq_imp_dvd: assumes "a \ 0" and "euclidean_size a = euclidean_size b" and "b dvd a" shows "a dvd b" proof (rule ccontr) assume "\ a dvd b" hence "b mod a \ 0" using mod_0_imp_dvd [of b a] by blast then have "b mod a \ 0" by (simp add: mod_eq_0_iff_dvd) from \b dvd a\ have "b dvd b mod a" by (simp add: dvd_mod_iff) then obtain c where "b mod a = b * c" unfolding dvd_def by blast with \b mod a \ 0\ have "c \ 0" by auto with \b mod a = b * c\ have "euclidean_size (b mod a) \ euclidean_size b" using size_mult_mono by force moreover from \\ a dvd b\ and \a \ 0\ have "euclidean_size (b mod a) < euclidean_size a" using mod_size_less by blast ultimately show False using \euclidean_size a = euclidean_size b\ by simp qed lemma euclidean_size_times_unit: assumes "is_unit a" shows "euclidean_size (a * b) = euclidean_size b" proof (rule antisym) from assms have [simp]: "a \ 0" by auto thus "euclidean_size (a * b) \ euclidean_size b" by (rule size_mult_mono') from assms have "is_unit (1 div a)" by simp hence "1 div a \ 0" by (intro notI) simp_all hence "euclidean_size (a * b) \ euclidean_size ((1 div a) * (a * b))" by (rule size_mult_mono') also from assms have "(1 div a) * (a * b) = b" by (simp add: algebra_simps unit_div_mult_swap) finally show "euclidean_size (a * b) \ euclidean_size b" . qed lemma euclidean_size_unit: "is_unit a \ euclidean_size a = euclidean_size 1" using euclidean_size_times_unit [of a 1] by simp lemma unit_iff_euclidean_size: "is_unit a \ euclidean_size a = euclidean_size 1 \ a \ 0" proof safe assume A: "a \ 0" and B: "euclidean_size a = euclidean_size 1" show "is_unit a" by (rule dvd_euclidean_size_eq_imp_dvd [OF A B]) simp_all qed (auto intro: euclidean_size_unit) lemma euclidean_size_times_nonunit: assumes "a \ 0" "b \ 0" "\ is_unit a" shows "euclidean_size b < euclidean_size (a * b)" proof (rule ccontr) assume "\euclidean_size b < euclidean_size (a * b)" with size_mult_mono'[OF assms(1), of b] have eq: "euclidean_size (a * b) = euclidean_size b" by simp have "a * b dvd b" by (rule dvd_euclidean_size_eq_imp_dvd [OF _ eq]) (insert assms, simp_all) hence "a * b dvd 1 * b" by simp with \b \ 0\ have "is_unit a" by (subst (asm) dvd_times_right_cancel_iff) with assms(3) show False by contradiction qed lemma dvd_imp_size_le: assumes "a dvd b" "b \ 0" shows "euclidean_size a \ euclidean_size b" using assms by (auto elim!: dvdE simp: size_mult_mono) lemma dvd_proper_imp_size_less: assumes "a dvd b" "\ b dvd a" "b \ 0" shows "euclidean_size a < euclidean_size b" proof - from assms(1) obtain c where "b = a * c" by (erule dvdE) hence z: "b = c * a" by (simp add: mult.commute) from z assms have "\is_unit c" by (auto simp: mult.commute mult_unit_dvd_iff) with z assms show ?thesis by (auto intro!: euclidean_size_times_nonunit) qed lemma unit_imp_mod_eq_0: "a mod b = 0" if "is_unit b" using that by (simp add: mod_eq_0_iff_dvd unit_imp_dvd) lemma mod_eq_self_iff_div_eq_0: "a mod b = a \ a div b = 0" (is "?P \ ?Q") proof assume ?P with div_mult_mod_eq [of a b] show ?Q by auto next assume ?Q with div_mult_mod_eq [of a b] show ?P by simp qed lemma coprime_mod_left_iff [simp]: "coprime (a mod b) b \ coprime a b" if "b \ 0" by (rule; rule coprimeI) (use that in \auto dest!: dvd_mod_imp_dvd coprime_common_divisor simp add: dvd_mod_iff\) lemma coprime_mod_right_iff [simp]: "coprime a (b mod a) \ coprime a b" if "a \ 0" using that coprime_mod_left_iff [of a b] by (simp add: ac_simps) end class euclidean_ring = idom_modulo + euclidean_semiring begin lemma dvd_diff_commute [ac_simps]: "a dvd c - b \ a dvd b - c" proof - have "a dvd c - b \ a dvd (c - b) * - 1" by (subst dvd_mult_unit_iff) simp_all then show ?thesis by simp qed end subsection \Euclidean (semi)rings with cancel rules\ class euclidean_semiring_cancel = euclidean_semiring + assumes div_mult_self1 [simp]: "b \ 0 \ (a + c * b) div b = c + a div b" and div_mult_mult1 [simp]: "c \ 0 \ (c * a) div (c * b) = a div b" begin lemma div_mult_self2 [simp]: assumes "b \ 0" shows "(a + b * c) div b = c + a div b" using assms div_mult_self1 [of b a c] by (simp add: mult.commute) lemma div_mult_self3 [simp]: assumes "b \ 0" shows "(c * b + a) div b = c + a div b" using assms by (simp add: add.commute) lemma div_mult_self4 [simp]: assumes "b \ 0" shows "(b * c + a) div b = c + a div b" using assms by (simp add: add.commute) lemma mod_mult_self1 [simp]: "(a + c * b) mod b = a mod b" proof (cases "b = 0") case True then show ?thesis by simp next case False have "a + c * b = (a + c * b) div b * b + (a + c * b) mod b" by (simp add: div_mult_mod_eq) also from False div_mult_self1 [of b a c] have "\ = (c + a div b) * b + (a + c * b) mod b" by (simp add: algebra_simps) finally have "a = a div b * b + (a + c * b) mod b" by (simp add: add.commute [of a] add.assoc distrib_right) then have "a div b * b + (a + c * b) mod b = a div b * b + a mod b" by (simp add: div_mult_mod_eq) then show ?thesis by simp qed lemma mod_mult_self2 [simp]: "(a + b * c) mod b = a mod b" by (simp add: mult.commute [of b]) lemma mod_mult_self3 [simp]: "(c * b + a) mod b = a mod b" by (simp add: add.commute) lemma mod_mult_self4 [simp]: "(b * c + a) mod b = a mod b" by (simp add: add.commute) lemma mod_mult_self1_is_0 [simp]: "b * a mod b = 0" using mod_mult_self2 [of 0 b a] by simp lemma mod_mult_self2_is_0 [simp]: "a * b mod b = 0" using mod_mult_self1 [of 0 a b] by simp lemma div_add_self1: assumes "b \ 0" shows "(b + a) div b = a div b + 1" using assms div_mult_self1 [of b a 1] by (simp add: add.commute) lemma div_add_self2: assumes "b \ 0" shows "(a + b) div b = a div b + 1" using assms div_add_self1 [of b a] by (simp add: add.commute) lemma mod_add_self1 [simp]: "(b + a) mod b = a mod b" using mod_mult_self1 [of a 1 b] by (simp add: add.commute) lemma mod_add_self2 [simp]: "(a + b) mod b = a mod b" using mod_mult_self1 [of a 1 b] by simp lemma mod_div_trivial [simp]: "a mod b div b = 0" proof (cases "b = 0") assume "b = 0" thus ?thesis by simp next assume "b \ 0" hence "a div b + a mod b div b = (a mod b + a div b * b) div b" by (rule div_mult_self1 [symmetric]) also have "\ = a div b" by (simp only: mod_div_mult_eq) also have "\ = a div b + 0" by simp finally show ?thesis by (rule add_left_imp_eq) qed lemma mod_mod_trivial [simp]: "a mod b mod b = a mod b" proof - have "a mod b mod b = (a mod b + a div b * b) mod b" by (simp only: mod_mult_self1) also have "\ = a mod b" by (simp only: mod_div_mult_eq) finally show ?thesis . qed lemma mod_mod_cancel: assumes "c dvd b" shows "a mod b mod c = a mod c" proof - from \c dvd b\ obtain k where "b = c * k" by (rule dvdE) have "a mod b mod c = a mod (c * k) mod c" by (simp only: \b = c * k\) also have "\ = (a mod (c * k) + a div (c * k) * k * c) mod c" by (simp only: mod_mult_self1) also have "\ = (a div (c * k) * (c * k) + a mod (c * k)) mod c" by (simp only: ac_simps) also have "\ = a mod c" by (simp only: div_mult_mod_eq) finally show ?thesis . qed lemma div_mult_mult2 [simp]: "c \ 0 \ (a * c) div (b * c) = a div b" by (drule div_mult_mult1) (simp add: mult.commute) lemma div_mult_mult1_if [simp]: "(c * a) div (c * b) = (if c = 0 then 0 else a div b)" by simp_all lemma mod_mult_mult1: "(c * a) mod (c * b) = c * (a mod b)" proof (cases "c = 0") case True then show ?thesis by simp next case False from div_mult_mod_eq have "((c * a) div (c * b)) * (c * b) + (c * a) mod (c * b) = c * a" . with False have "c * ((a div b) * b + a mod b) + (c * a) mod (c * b) = c * a + c * (a mod b)" by (simp add: algebra_simps) with div_mult_mod_eq show ?thesis by simp qed lemma mod_mult_mult2: "(a * c) mod (b * c) = (a mod b) * c" using mod_mult_mult1 [of c a b] by (simp add: mult.commute) lemma mult_mod_left: "(a mod b) * c = (a * c) mod (b * c)" by (fact mod_mult_mult2 [symmetric]) lemma mult_mod_right: "c * (a mod b) = (c * a) mod (c * b)" by (fact mod_mult_mult1 [symmetric]) lemma dvd_mod: "k dvd m \ k dvd n \ k dvd (m mod n)" unfolding dvd_def by (auto simp add: mod_mult_mult1) lemma div_plus_div_distrib_dvd_left: "c dvd a \ (a + b) div c = a div c + b div c" by (cases "c = 0") (auto elim: dvdE) lemma div_plus_div_distrib_dvd_right: "c dvd b \ (a + b) div c = a div c + b div c" using div_plus_div_distrib_dvd_left [of c b a] by (simp add: ac_simps) named_theorems mod_simps text \Addition respects modular equivalence.\ lemma mod_add_left_eq [mod_simps]: "(a mod c + b) mod c = (a + b) mod c" proof - have "(a + b) mod c = (a div c * c + a mod c + b) mod c" by (simp only: div_mult_mod_eq) also have "\ = (a mod c + b + a div c * c) mod c" by (simp only: ac_simps) also have "\ = (a mod c + b) mod c" by (rule mod_mult_self1) finally show ?thesis by (rule sym) qed lemma mod_add_right_eq [mod_simps]: "(a + b mod c) mod c = (a + b) mod c" using mod_add_left_eq [of b c a] by (simp add: ac_simps) lemma mod_add_eq: "(a mod c + b mod c) mod c = (a + b) mod c" by (simp add: mod_add_left_eq mod_add_right_eq) lemma mod_sum_eq [mod_simps]: "(\i\A. f i mod a) mod a = sum f A mod a" proof (induct A rule: infinite_finite_induct) case (insert i A) then have "(\i\insert i A. f i mod a) mod a = (f i mod a + (\i\A. f i mod a)) mod a" by simp also have "\ = (f i + (\i\A. f i mod a) mod a) mod a" by (simp add: mod_simps) also have "\ = (f i + (\i\A. f i) mod a) mod a" by (simp add: insert.hyps) finally show ?case by (simp add: insert.hyps mod_simps) qed simp_all lemma mod_add_cong: assumes "a mod c = a' mod c" assumes "b mod c = b' mod c" shows "(a + b) mod c = (a' + b') mod c" proof - have "(a mod c + b mod c) mod c = (a' mod c + b' mod c) mod c" unfolding assms .. then show ?thesis by (simp add: mod_add_eq) qed text \Multiplication respects modular equivalence.\ lemma mod_mult_left_eq [mod_simps]: "((a mod c) * b) mod c = (a * b) mod c" proof - have "(a * b) mod c = ((a div c * c + a mod c) * b) mod c" by (simp only: div_mult_mod_eq) also have "\ = (a mod c * b + a div c * b * c) mod c" by (simp only: algebra_simps) also have "\ = (a mod c * b) mod c" by (rule mod_mult_self1) finally show ?thesis by (rule sym) qed lemma mod_mult_right_eq [mod_simps]: "(a * (b mod c)) mod c = (a * b) mod c" using mod_mult_left_eq [of b c a] by (simp add: ac_simps) lemma mod_mult_eq: "((a mod c) * (b mod c)) mod c = (a * b) mod c" by (simp add: mod_mult_left_eq mod_mult_right_eq) lemma mod_prod_eq [mod_simps]: "(\i\A. f i mod a) mod a = prod f A mod a" proof (induct A rule: infinite_finite_induct) case (insert i A) then have "(\i\insert i A. f i mod a) mod a = (f i mod a * (\i\A. f i mod a)) mod a" by simp also have "\ = (f i * ((\i\A. f i mod a) mod a)) mod a" by (simp add: mod_simps) also have "\ = (f i * ((\i\A. f i) mod a)) mod a" by (simp add: insert.hyps) finally show ?case by (simp add: insert.hyps mod_simps) qed simp_all lemma mod_mult_cong: assumes "a mod c = a' mod c" assumes "b mod c = b' mod c" shows "(a * b) mod c = (a' * b') mod c" proof - have "(a mod c * (b mod c)) mod c = (a' mod c * (b' mod c)) mod c" unfolding assms .. then show ?thesis by (simp add: mod_mult_eq) qed text \Exponentiation respects modular equivalence.\ lemma power_mod [mod_simps]: "((a mod b) ^ n) mod b = (a ^ n) mod b" proof (induct n) case 0 then show ?case by simp next case (Suc n) have "(a mod b) ^ Suc n mod b = (a mod b) * ((a mod b) ^ n mod b) mod b" by (simp add: mod_mult_right_eq) with Suc show ?case by (simp add: mod_mult_left_eq mod_mult_right_eq) qed end class euclidean_ring_cancel = euclidean_ring + euclidean_semiring_cancel begin subclass idom_divide .. lemma div_minus_minus [simp]: "(- a) div (- b) = a div b" using div_mult_mult1 [of "- 1" a b] by simp lemma mod_minus_minus [simp]: "(- a) mod (- b) = - (a mod b)" using mod_mult_mult1 [of "- 1" a b] by simp lemma div_minus_right: "a div (- b) = (- a) div b" using div_minus_minus [of "- a" b] by simp lemma mod_minus_right: "a mod (- b) = - ((- a) mod b)" using mod_minus_minus [of "- a" b] by simp lemma div_minus1_right [simp]: "a div (- 1) = - a" using div_minus_right [of a 1] by simp lemma mod_minus1_right [simp]: "a mod (- 1) = 0" using mod_minus_right [of a 1] by simp text \Negation respects modular equivalence.\ lemma mod_minus_eq [mod_simps]: "(- (a mod b)) mod b = (- a) mod b" proof - have "(- a) mod b = (- (a div b * b + a mod b)) mod b" by (simp only: div_mult_mod_eq) also have "\ = (- (a mod b) + - (a div b) * b) mod b" by (simp add: ac_simps) also have "\ = (- (a mod b)) mod b" by (rule mod_mult_self1) finally show ?thesis by (rule sym) qed lemma mod_minus_cong: assumes "a mod b = a' mod b" shows "(- a) mod b = (- a') mod b" proof - have "(- (a mod b)) mod b = (- (a' mod b)) mod b" unfolding assms .. then show ?thesis by (simp add: mod_minus_eq) qed text \Subtraction respects modular equivalence.\ lemma mod_diff_left_eq [mod_simps]: "(a mod c - b) mod c = (a - b) mod c" using mod_add_cong [of a c "a mod c" "- b" "- b"] by simp lemma mod_diff_right_eq [mod_simps]: "(a - b mod c) mod c = (a - b) mod c" using mod_add_cong [of a c a "- b" "- (b mod c)"] mod_minus_cong [of "b mod c" c b] by simp lemma mod_diff_eq: "(a mod c - b mod c) mod c = (a - b) mod c" using mod_add_cong [of a c "a mod c" "- b" "- (b mod c)"] mod_minus_cong [of "b mod c" c b] by simp lemma mod_diff_cong: assumes "a mod c = a' mod c" assumes "b mod c = b' mod c" shows "(a - b) mod c = (a' - b') mod c" using assms mod_add_cong [of a c a' "- b" "- b'"] mod_minus_cong [of b c "b'"] by simp lemma minus_mod_self2 [simp]: "(a - b) mod b = a mod b" using mod_diff_right_eq [of a b b] by (simp add: mod_diff_right_eq) lemma minus_mod_self1 [simp]: "(b - a) mod b = - a mod b" using mod_add_self2 [of "- a" b] by simp lemma mod_eq_dvd_iff: "a mod c = b mod c \ c dvd a - b" (is "?P \ ?Q") proof assume ?P then have "(a mod c - b mod c) mod c = 0" by simp then show ?Q by (simp add: dvd_eq_mod_eq_0 mod_simps) next assume ?Q then obtain d where d: "a - b = c * d" .. then have "a = c * d + b" by (simp add: algebra_simps) then show ?P by simp qed lemma mod_eqE: assumes "a mod c = b mod c" obtains d where "b = a + c * d" proof - from assms have "c dvd a - b" by (simp add: mod_eq_dvd_iff) then obtain d where "a - b = c * d" .. then have "b = a + c * - d" by (simp add: algebra_simps) with that show thesis . qed lemma invertible_coprime: "coprime a c" if "a * b mod c = 1" by (rule coprimeI) (use that dvd_mod_iff [of _ c "a * b"] in auto) end subsection \Uniquely determined division\ class unique_euclidean_semiring = euclidean_semiring + assumes euclidean_size_mult: "euclidean_size (a * b) = euclidean_size a * euclidean_size b" fixes division_segment :: "'a \ 'a" assumes is_unit_division_segment [simp]: "is_unit (division_segment a)" and division_segment_mult: "a \ 0 \ b \ 0 \ division_segment (a * b) = division_segment a * division_segment b" and division_segment_mod: "b \ 0 \ \ b dvd a \ division_segment (a mod b) = division_segment b" assumes div_bounded: "b \ 0 \ division_segment r = division_segment b \ euclidean_size r < euclidean_size b \ (q * b + r) div b = q" begin lemma division_segment_not_0 [simp]: "division_segment a \ 0" using is_unit_division_segment [of a] is_unitE [of "division_segment a"] by blast lemma divmod_cases [case_names divides remainder by0]: obtains (divides) q where "b \ 0" and "a div b = q" and "a mod b = 0" and "a = q * b" | (remainder) q r where "b \ 0" and "division_segment r = division_segment b" and "euclidean_size r < euclidean_size b" and "r \ 0" and "a div b = q" and "a mod b = r" and "a = q * b + r" | (by0) "b = 0" proof (cases "b = 0") case True then show thesis by (rule by0) next case False show thesis proof (cases "b dvd a") case True then obtain q where "a = b * q" .. with \b \ 0\ divides show thesis by (simp add: ac_simps) next case False then have "a mod b \ 0" by (simp add: mod_eq_0_iff_dvd) moreover from \b \ 0\ \\ b dvd a\ have "division_segment (a mod b) = division_segment b" by (rule division_segment_mod) moreover have "euclidean_size (a mod b) < euclidean_size b" using \b \ 0\ by (rule mod_size_less) moreover have "a = a div b * b + a mod b" by (simp add: div_mult_mod_eq) ultimately show thesis using \b \ 0\ by (blast intro!: remainder) qed qed lemma div_eqI: "a div b = q" if "b \ 0" "division_segment r = division_segment b" "euclidean_size r < euclidean_size b" "q * b + r = a" proof - from that have "(q * b + r) div b = q" by (auto intro: div_bounded) with that show ?thesis by simp qed lemma mod_eqI: "a mod b = r" if "b \ 0" "division_segment r = division_segment b" "euclidean_size r < euclidean_size b" "q * b + r = a" proof - from that have "a div b = q" by (rule div_eqI) moreover have "a div b * b + a mod b = a" by (fact div_mult_mod_eq) ultimately have "a div b * b + a mod b = a div b * b + r" using \q * b + r = a\ by simp then show ?thesis by simp qed subclass euclidean_semiring_cancel proof show "(a + c * b) div b = c + a div b" if "b \ 0" for a b c proof (cases a b rule: divmod_cases) case by0 with \b \ 0\ show ?thesis by simp next case (divides q) then show ?thesis by (simp add: ac_simps) next case (remainder q r) then show ?thesis by (auto intro: div_eqI simp add: algebra_simps) qed next show"(c * a) div (c * b) = a div b" if "c \ 0" for a b c proof (cases a b rule: divmod_cases) case by0 then show ?thesis by simp next case (divides q) with \c \ 0\ show ?thesis by (simp add: mult.left_commute [of c]) next case (remainder q r) from \b \ 0\ \c \ 0\ have "b * c \ 0" by simp from remainder \c \ 0\ have "division_segment (r * c) = division_segment (b * c)" and "euclidean_size (r * c) < euclidean_size (b * c)" by (simp_all add: division_segment_mult division_segment_mod euclidean_size_mult) with remainder show ?thesis by (auto intro!: div_eqI [of _ "c * (a mod b)"] simp add: algebra_simps) (use \b * c \ 0\ in simp) qed qed lemma div_mult1_eq: "(a * b) div c = a * (b div c) + a * (b mod c) div c" proof (cases "a * (b mod c)" c rule: divmod_cases) case (divides q) have "a * b = a * (b div c * c + b mod c)" by (simp add: div_mult_mod_eq) also have "\ = (a * (b div c) + q) * c" using divides by (simp add: algebra_simps) finally have "(a * b) div c = \ div c" by simp with divides show ?thesis by simp next case (remainder q r) from remainder(1-3) show ?thesis proof (rule div_eqI) have "a * b = a * (b div c * c + b mod c)" by (simp add: div_mult_mod_eq) also have "\ = a * c * (b div c) + q * c + r" using remainder by (simp add: algebra_simps) finally show "(a * (b div c) + a * (b mod c) div c) * c + r = a * b" using remainder(5-7) by (simp add: algebra_simps) qed next case by0 then show ?thesis by simp qed lemma div_add1_eq: "(a + b) div c = a div c + b div c + (a mod c + b mod c) div c" proof (cases "a mod c + b mod c" c rule: divmod_cases) case (divides q) have "a + b = (a div c * c + a mod c) + (b div c * c + b mod c)" using mod_mult_div_eq [of a c] mod_mult_div_eq [of b c] by (simp add: ac_simps) also have "\ = (a div c + b div c) * c + (a mod c + b mod c)" by (simp add: algebra_simps) also have "\ = (a div c + b div c + q) * c" using divides by (simp add: algebra_simps) finally have "(a + b) div c = (a div c + b div c + q) * c div c" by simp with divides show ?thesis by simp next case (remainder q r) from remainder(1-3) show ?thesis proof (rule div_eqI) have "(a div c + b div c + q) * c + r + (a mod c + b mod c) = (a div c * c + a mod c) + (b div c * c + b mod c) + q * c + r" by (simp add: algebra_simps) also have "\ = a + b + (a mod c + b mod c)" by (simp add: div_mult_mod_eq remainder) (simp add: ac_simps) finally show "(a div c + b div c + (a mod c + b mod c) div c) * c + r = a + b" using remainder by simp qed next case by0 then show ?thesis by simp qed lemma div_eq_0_iff: "a div b = 0 \ euclidean_size a < euclidean_size b \ b = 0" (is "_ \ ?P") if "division_segment a = division_segment b" proof assume ?P with that show "a div b = 0" by (cases "b = 0") (auto intro: div_eqI) next assume "a div b = 0" then have "a mod b = a" using div_mult_mod_eq [of a b] by simp with mod_size_less [of b a] show ?P by auto qed end class unique_euclidean_ring = euclidean_ring + unique_euclidean_semiring begin subclass euclidean_ring_cancel .. end subsection \Euclidean division on \<^typ>\nat\\ instantiation nat :: normalization_semidom begin definition normalize_nat :: "nat \ nat" where [simp]: "normalize = (id :: nat \ nat)" definition unit_factor_nat :: "nat \ nat" where "unit_factor n = (if n = 0 then 0 else 1 :: nat)" lemma unit_factor_simps [simp]: "unit_factor 0 = (0::nat)" "unit_factor (Suc n) = 1" by (simp_all add: unit_factor_nat_def) definition divide_nat :: "nat \ nat \ nat" where "m div n = (if n = 0 then 0 else Max {k::nat. k * n \ m})" instance by standard (auto simp add: divide_nat_def ac_simps unit_factor_nat_def intro: Max_eqI) end lemma coprime_Suc_0_left [simp]: "coprime (Suc 0) n" using coprime_1_left [of n] by simp lemma coprime_Suc_0_right [simp]: "coprime n (Suc 0)" using coprime_1_right [of n] by simp lemma coprime_common_divisor_nat: "coprime a b \ x dvd a \ x dvd b \ x = 1" for a b :: nat by (drule coprime_common_divisor [of _ _ x]) simp_all instantiation nat :: unique_euclidean_semiring begin definition euclidean_size_nat :: "nat \ nat" where [simp]: "euclidean_size_nat = id" definition division_segment_nat :: "nat \ nat" where [simp]: "division_segment_nat n = 1" definition modulo_nat :: "nat \ nat \ nat" where "m mod n = m - (m div n * (n::nat))" instance proof fix m n :: nat have ex: "\k. k * n \ l" for l :: nat by (rule exI [of _ 0]) simp have fin: "finite {k. k * n \ l}" if "n > 0" for l proof - from that have "{k. k * n \ l} \ {k. k \ l}" by (cases n) auto then show ?thesis by (rule finite_subset) simp qed have mult_div_unfold: "n * (m div n) = Max {l. l \ m \ n dvd l}" proof (cases "n = 0") case True moreover have "{l. l = 0 \ l \ m} = {0::nat}" by auto ultimately show ?thesis by simp next case False with ex [of m] fin have "n * Max {k. k * n \ m} = Max (times n ` {k. k * n \ m})" by (auto simp add: nat_mult_max_right intro: hom_Max_commute) also have "times n ` {k. k * n \ m} = {l. l \ m \ n dvd l}" by (auto simp add: ac_simps elim!: dvdE) finally show ?thesis using False by (simp add: divide_nat_def ac_simps) qed have less_eq: "m div n * n \ m" by (auto simp add: mult_div_unfold ac_simps intro: Max.boundedI) then show "m div n * n + m mod n = m" by (simp add: modulo_nat_def) assume "n \ 0" show "euclidean_size (m mod n) < euclidean_size n" proof - have "m < Suc (m div n) * n" proof (rule ccontr) assume "\ m < Suc (m div n) * n" then have "Suc (m div n) * n \ m" by (simp add: not_less) moreover from \n \ 0\ have "Max {k. k * n \ m} < Suc (m div n)" by (simp add: divide_nat_def) with \n \ 0\ ex fin have "\k. k * n \ m \ k < Suc (m div n)" by auto ultimately have "Suc (m div n) < Suc (m div n)" by blast then show False by simp qed with \n \ 0\ show ?thesis by (simp add: modulo_nat_def) qed show "euclidean_size m \ euclidean_size (m * n)" using \n \ 0\ by (cases n) simp_all fix q r :: nat show "(q * n + r) div n = q" if "euclidean_size r < euclidean_size n" proof - from that have "r < n" by simp have "k \ q" if "k * n \ q * n + r" for k proof (rule ccontr) assume "\ k \ q" then have "q < k" by simp then obtain l where "k = Suc (q + l)" by (auto simp add: less_iff_Suc_add) with \r < n\ that show False by (simp add: algebra_simps) qed with \n \ 0\ ex fin show ?thesis by (auto simp add: divide_nat_def Max_eq_iff) qed qed simp_all end text \Tool support\ ML \ structure Cancel_Div_Mod_Nat = Cancel_Div_Mod ( val div_name = \<^const_name>\divide\; val mod_name = \<^const_name>\modulo\; val mk_binop = HOLogic.mk_binop; val dest_plus = HOLogic.dest_bin \<^const_name>\Groups.plus\ HOLogic.natT; val mk_sum = Arith_Data.mk_sum; fun dest_sum tm = if HOLogic.is_zero tm then [] else (case try HOLogic.dest_Suc tm of SOME t => HOLogic.Suc_zero :: dest_sum t | NONE => (case try dest_plus tm of SOME (t, u) => dest_sum t @ dest_sum u | NONE => [tm])); val div_mod_eqs = map mk_meta_eq @{thms cancel_div_mod_rules}; val prove_eq_sums = Arith_Data.prove_conv2 all_tac (Arith_Data.simp_all_tac @{thms add_0_left add_0_right ac_simps}) ) \ simproc_setup cancel_div_mod_nat ("(m::nat) + n") = \K Cancel_Div_Mod_Nat.proc\ lemma div_nat_eqI: "m div n = q" if "n * q \ m" and "m < n * Suc q" for m n q :: nat by (rule div_eqI [of _ "m - n * q"]) (use that in \simp_all add: algebra_simps\) lemma mod_nat_eqI: "m mod n = r" if "r < n" and "r \ m" and "n dvd m - r" for m n r :: nat by (rule mod_eqI [of _ _ "(m - r) div n"]) (use that in \simp_all add: algebra_simps\) lemma div_mult_self_is_m [simp]: "m * n div n = m" if "n > 0" for m n :: nat using that by simp lemma div_mult_self1_is_m [simp]: "n * m div n = m" if "n > 0" for m n :: nat using that by simp lemma mod_less_divisor [simp]: "m mod n < n" if "n > 0" for m n :: nat using mod_size_less [of n m] that by simp lemma mod_le_divisor [simp]: "m mod n \ n" if "n > 0" for m n :: nat using that by (auto simp add: le_less) lemma div_times_less_eq_dividend [simp]: "m div n * n \ m" for m n :: nat by (simp add: minus_mod_eq_div_mult [symmetric]) lemma times_div_less_eq_dividend [simp]: "n * (m div n) \ m" for m n :: nat using div_times_less_eq_dividend [of m n] by (simp add: ac_simps) lemma dividend_less_div_times: "m < n + (m div n) * n" if "0 < n" for m n :: nat proof - from that have "m mod n < n" by simp then show ?thesis by (simp add: minus_mod_eq_div_mult [symmetric]) qed lemma dividend_less_times_div: "m < n + n * (m div n)" if "0 < n" for m n :: nat using dividend_less_div_times [of n m] that by (simp add: ac_simps) lemma mod_Suc_le_divisor [simp]: "m mod Suc n \ n" using mod_less_divisor [of "Suc n" m] by arith lemma mod_less_eq_dividend [simp]: "m mod n \ m" for m n :: nat proof (rule add_leD2) from div_mult_mod_eq have "m div n * n + m mod n = m" . then show "m div n * n + m mod n \ m" by auto qed lemma div_less [simp]: "m div n = 0" and mod_less [simp]: "m mod n = m" if "m < n" for m n :: nat using that by (auto intro: div_eqI mod_eqI) lemma le_div_geq: "m div n = Suc ((m - n) div n)" if "0 < n" and "n \ m" for m n :: nat proof - from \n \ m\ obtain q where "m = n + q" by (auto simp add: le_iff_add) with \0 < n\ show ?thesis by (simp add: div_add_self1) qed lemma le_mod_geq: "m mod n = (m - n) mod n" if "n \ m" for m n :: nat proof - from \n \ m\ obtain q where "m = n + q" by (auto simp add: le_iff_add) then show ?thesis by simp qed lemma div_if: "m div n = (if m < n \ n = 0 then 0 else Suc ((m - n) div n))" by (simp add: le_div_geq) lemma mod_if: "m mod n = (if m < n then m else (m - n) mod n)" for m n :: nat by (simp add: le_mod_geq) lemma div_eq_0_iff: "m div n = 0 \ m < n \ n = 0" for m n :: nat by (simp add: div_eq_0_iff) lemma div_greater_zero_iff: "m div n > 0 \ n \ m \ n > 0" for m n :: nat using div_eq_0_iff [of m n] by auto lemma mod_greater_zero_iff_not_dvd: "m mod n > 0 \ \ n dvd m" for m n :: nat by (simp add: dvd_eq_mod_eq_0) lemma div_by_Suc_0 [simp]: "m div Suc 0 = m" using div_by_1 [of m] by simp lemma mod_by_Suc_0 [simp]: "m mod Suc 0 = 0" using mod_by_1 [of m] by simp lemma div2_Suc_Suc [simp]: "Suc (Suc m) div 2 = Suc (m div 2)" by (simp add: numeral_2_eq_2 le_div_geq) lemma Suc_n_div_2_gt_zero [simp]: "0 < Suc n div 2" if "n > 0" for n :: nat using that by (cases n) simp_all lemma div_2_gt_zero [simp]: "0 < n div 2" if "Suc 0 < n" for n :: nat using that Suc_n_div_2_gt_zero [of "n - 1"] by simp lemma mod2_Suc_Suc [simp]: "Suc (Suc m) mod 2 = m mod 2" by (simp add: numeral_2_eq_2 le_mod_geq) lemma add_self_div_2 [simp]: "(m + m) div 2 = m" for m :: nat by (simp add: mult_2 [symmetric]) lemma add_self_mod_2 [simp]: "(m + m) mod 2 = 0" for m :: nat by (simp add: mult_2 [symmetric]) lemma mod2_gr_0 [simp]: "0 < m mod 2 \ m mod 2 = 1" for m :: nat proof - have "m mod 2 < 2" by (rule mod_less_divisor) simp then have "m mod 2 = 0 \ m mod 2 = 1" by arith then show ?thesis by auto qed lemma mod_Suc_eq [mod_simps]: "Suc (m mod n) mod n = Suc m mod n" proof - have "(m mod n + 1) mod n = (m + 1) mod n" by (simp only: mod_simps) then show ?thesis by simp qed lemma mod_Suc_Suc_eq [mod_simps]: "Suc (Suc (m mod n)) mod n = Suc (Suc m) mod n" proof - have "(m mod n + 2) mod n = (m + 2) mod n" by (simp only: mod_simps) then show ?thesis by simp qed lemma Suc_mod_mult_self1 [simp]: "Suc (m + k * n) mod n = Suc m mod n" and Suc_mod_mult_self2 [simp]: "Suc (m + n * k) mod n = Suc m mod n" and Suc_mod_mult_self3 [simp]: "Suc (k * n + m) mod n = Suc m mod n" and Suc_mod_mult_self4 [simp]: "Suc (n * k + m) mod n = Suc m mod n" by (subst mod_Suc_eq [symmetric], simp add: mod_simps)+ lemma Suc_0_mod_eq [simp]: "Suc 0 mod n = of_bool (n \ Suc 0)" by (cases n) simp_all context fixes m n q :: nat begin private lemma eucl_rel_mult2: "m mod n + n * (m div n mod q) < n * q" if "n > 0" and "q > 0" proof - from \n > 0\ have "m mod n < n" by (rule mod_less_divisor) from \q > 0\ have "m div n mod q < q" by (rule mod_less_divisor) then obtain s where "q = Suc (m div n mod q + s)" by (blast dest: less_imp_Suc_add) moreover have "m mod n + n * (m div n mod q) < n * Suc (m div n mod q + s)" using \m mod n < n\ by (simp add: add_mult_distrib2) ultimately show ?thesis by simp qed lemma div_mult2_eq: "m div (n * q) = (m div n) div q" proof (cases "n = 0 \ q = 0") case True then show ?thesis by auto next case False with eucl_rel_mult2 show ?thesis by (auto intro: div_eqI [of _ "n * (m div n mod q) + m mod n"] simp add: algebra_simps add_mult_distrib2 [symmetric]) qed lemma mod_mult2_eq: "m mod (n * q) = n * (m div n mod q) + m mod n" proof (cases "n = 0 \ q = 0") case True then show ?thesis by auto next case False with eucl_rel_mult2 show ?thesis by (auto intro: mod_eqI [of _ _ "(m div n) div q"] simp add: algebra_simps add_mult_distrib2 [symmetric]) qed end lemma div_le_mono: "m div k \ n div k" if "m \ n" for m n k :: nat proof - from that obtain q where "n = m + q" by (auto simp add: le_iff_add) then show ?thesis by (simp add: div_add1_eq [of m q k]) qed text \Antimonotonicity of \<^const>\divide\ in second argument\ lemma div_le_mono2: "k div n \ k div m" if "0 < m" and "m \ n" for m n k :: nat using that proof (induct k arbitrary: m rule: less_induct) case (less k) show ?case proof (cases "n \ k") case False then show ?thesis by simp next case True have "(k - n) div n \ (k - m) div n" using less.prems by (blast intro: div_le_mono diff_le_mono2) also have "\ \ (k - m) div m" using \n \ k\ less.prems less.hyps [of "k - m" m] by simp finally show ?thesis using \n \ k\ less.prems by (simp add: le_div_geq) qed qed lemma div_le_dividend [simp]: "m div n \ m" for m n :: nat using div_le_mono2 [of 1 n m] by (cases "n = 0") simp_all lemma div_less_dividend [simp]: "m div n < m" if "1 < n" and "0 < m" for m n :: nat using that proof (induct m rule: less_induct) case (less m) show ?case proof (cases "n < m") case False with less show ?thesis by (cases "n = m") simp_all next case True then show ?thesis using less.hyps [of "m - n"] less.prems by (simp add: le_div_geq) qed qed lemma div_eq_dividend_iff: "m div n = m \ n = 1" if "m > 0" for m n :: nat proof assume "n = 1" then show "m div n = m" by simp next assume P: "m div n = m" show "n = 1" proof (rule ccontr) have "n \ 0" by (rule ccontr) (use that P in auto) moreover assume "n \ 1" ultimately have "n > 1" by simp with that have "m div n < m" by simp with P show False by simp qed qed lemma less_mult_imp_div_less: "m div n < i" if "m < i * n" for m n i :: nat proof - from that have "i * n > 0" by (cases "i * n = 0") simp_all then have "i > 0" and "n > 0" by simp_all have "m div n * n \ m" by simp then have "m div n * n < i * n" using that by (rule le_less_trans) with \n > 0\ show ?thesis by simp qed text \A fact for the mutilated chess board\ lemma mod_Suc: "Suc m mod n = (if Suc (m mod n) = n then 0 else Suc (m mod n))" (is "_ = ?rhs") proof (cases "n = 0") case True then show ?thesis by simp next case False have "Suc m mod n = Suc (m mod n) mod n" by (simp add: mod_simps) also have "\ = ?rhs" using False by (auto intro!: mod_nat_eqI intro: neq_le_trans simp add: Suc_le_eq) finally show ?thesis . qed lemma Suc_times_mod_eq: "Suc (m * n) mod m = 1" if "Suc 0 < m" using that by (simp add: mod_Suc) lemma Suc_times_numeral_mod_eq [simp]: "Suc (numeral k * n) mod numeral k = 1" if "numeral k \ (1::nat)" by (rule Suc_times_mod_eq) (use that in simp) lemma Suc_div_le_mono [simp]: "m div n \ Suc m div n" by (simp add: div_le_mono) text \These lemmas collapse some needless occurrences of Suc: at least three Sucs, since two and fewer are rewritten back to Suc again! We already have some rules to simplify operands smaller than 3.\ lemma div_Suc_eq_div_add3 [simp]: "m div Suc (Suc (Suc n)) = m div (3 + n)" by (simp add: Suc3_eq_add_3) lemma mod_Suc_eq_mod_add3 [simp]: "m mod Suc (Suc (Suc n)) = m mod (3 + n)" by (simp add: Suc3_eq_add_3) lemma Suc_div_eq_add3_div: "Suc (Suc (Suc m)) div n = (3 + m) div n" by (simp add: Suc3_eq_add_3) lemma Suc_mod_eq_add3_mod: "Suc (Suc (Suc m)) mod n = (3 + m) mod n" by (simp add: Suc3_eq_add_3) lemmas Suc_div_eq_add3_div_numeral [simp] = Suc_div_eq_add3_div [of _ "numeral v"] for v lemmas Suc_mod_eq_add3_mod_numeral [simp] = Suc_mod_eq_add3_mod [of _ "numeral v"] for v lemma (in field_char_0) of_nat_div: "of_nat (m div n) = ((of_nat m - of_nat (m mod n)) / of_nat n)" proof - have "of_nat (m div n) = ((of_nat (m div n * n + m mod n) - of_nat (m mod n)) / of_nat n :: 'a)" unfolding of_nat_add by (cases "n = 0") simp_all then show ?thesis by simp qed text \An ``induction'' law for modulus arithmetic.\ lemma mod_induct [consumes 3, case_names step]: "P m" if "P n" and "n < p" and "m < p" and step: "\n. n < p \ P n \ P (Suc n mod p)" using \m < p\ proof (induct m) case 0 show ?case proof (rule ccontr) assume "\ P 0" from \n < p\ have "0 < p" by simp from \n < p\ obtain m where "0 < m" and "p = n + m" by (blast dest: less_imp_add_positive) with \P n\ have "P (p - m)" by simp moreover have "\ P (p - m)" using \0 < m\ proof (induct m) case 0 then show ?case by simp next case (Suc m) show ?case proof assume P: "P (p - Suc m)" with \\ P 0\ have "Suc m < p" by (auto intro: ccontr) then have "Suc (p - Suc m) = p - m" by arith moreover from \0 < p\ have "p - Suc m < p" by arith with P step have "P ((Suc (p - Suc m)) mod p)" by blast ultimately show False using \\ P 0\ Suc.hyps by (cases "m = 0") simp_all qed qed ultimately show False by blast qed next case (Suc m) then have "m < p" and mod: "Suc m mod p = Suc m" by simp_all from \m < p\ have "P m" by (rule Suc.hyps) with \m < p\ have "P (Suc m mod p)" by (rule step) with mod show ?case by simp qed lemma split_div: "P (m div n) \ (n = 0 \ P 0) \ (n \ 0 \ (\i j. j < n \ m = n * i + j \ P i))" (is "?P = ?Q") for m n :: nat proof (cases "n = 0") case True then show ?thesis by simp next case False show ?thesis proof assume ?P with False show ?Q by auto next assume ?Q with False have *: "\i j. j < n \ m = n * i + j \ P i" by simp with False show ?P by (auto intro: * [of "m mod n"]) qed qed lemma split_div': "P (m div n) \ n = 0 \ P 0 \ (\q. (n * q \ m \ m < n * Suc q) \ P q)" proof (cases "n = 0") case True then show ?thesis by simp next case False then have "n * q \ m \ m < n * Suc q \ m div n = q" for q by (auto intro: div_nat_eqI dividend_less_times_div) then show ?thesis by auto qed lemma split_mod: "P (m mod n) \ (n = 0 \ P m) \ (n \ 0 \ (\i j. j < n \ m = n * i + j \ P j))" (is "?P \ ?Q") for m n :: nat proof (cases "n = 0") case True then show ?thesis by simp next case False show ?thesis proof assume ?P with False show ?Q by auto next assume ?Q with False have *: "\i j. j < n \ m = n * i + j \ P j" by simp with False show ?P by (auto intro: * [of _ "m div n"]) qed qed subsection \Euclidean division on \<^typ>\int\\ instantiation int :: normalization_semidom begin definition normalize_int :: "int \ int" where [simp]: "normalize = (abs :: int \ int)" definition unit_factor_int :: "int \ int" where [simp]: "unit_factor = (sgn :: int \ int)" definition divide_int :: "int \ int \ int" where "k div l = (if l = 0 then 0 else if sgn k = sgn l then int (nat \k\ div nat \l\) else - int (nat \k\ div nat \l\ + of_bool (\ l dvd k)))" lemma divide_int_unfold: "(sgn k * int m) div (sgn l * int n) = (if sgn l = 0 \ sgn k = 0 \ n = 0 then 0 else if sgn k = sgn l then int (m div n) else - int (m div n + of_bool (\ n dvd m)))" by (auto simp add: divide_int_def sgn_0_0 sgn_1_pos sgn_mult abs_mult nat_mult_distrib) instance proof fix k :: int show "k div 0 = 0" by (simp add: divide_int_def) next fix k l :: int assume "l \ 0" obtain n m and s t where k: "k = sgn s * int n" and l: "l = sgn t * int m" by (blast intro: int_sgnE elim: that) then have "k * l = sgn (s * t) * int (n * m)" by (simp add: ac_simps sgn_mult) with k l \l \ 0\ show "k * l div l = k" by (simp only: divide_int_unfold) (auto simp add: algebra_simps sgn_mult sgn_1_pos sgn_0_0) qed (auto simp add: sgn_mult mult_sgn_abs abs_eq_iff') end lemma coprime_int_iff [simp]: "coprime (int m) (int n) \ coprime m n" (is "?P \ ?Q") proof assume ?P show ?Q proof (rule coprimeI) fix q assume "q dvd m" "q dvd n" then have "int q dvd int m" "int q dvd int n" by simp_all with \?P\ have "is_unit (int q)" by (rule coprime_common_divisor) then show "is_unit q" by simp qed next assume ?Q show ?P proof (rule coprimeI) fix k assume "k dvd int m" "k dvd int n" then have "nat \k\ dvd m" "nat \k\ dvd n" by simp_all with \?Q\ have "is_unit (nat \k\)" by (rule coprime_common_divisor) then show "is_unit k" by simp qed qed lemma coprime_abs_left_iff [simp]: "coprime \k\ l \ coprime k l" for k l :: int using coprime_normalize_left_iff [of k l] by simp lemma coprime_abs_right_iff [simp]: "coprime k \l\ \ coprime k l" for k l :: int using coprime_abs_left_iff [of l k] by (simp add: ac_simps) lemma coprime_nat_abs_left_iff [simp]: "coprime (nat \k\) n \ coprime k (int n)" proof - define m where "m = nat \k\" then have "\k\ = int m" by simp moreover have "coprime k (int n) \ coprime \k\ (int n)" by simp ultimately show ?thesis by simp qed lemma coprime_nat_abs_right_iff [simp]: "coprime n (nat \k\) \ coprime (int n) k" using coprime_nat_abs_left_iff [of k n] by (simp add: ac_simps) lemma coprime_common_divisor_int: "coprime a b \ x dvd a \ x dvd b \ \x\ = 1" for a b :: int by (drule coprime_common_divisor [of _ _ x]) simp_all instantiation int :: idom_modulo begin definition modulo_int :: "int \ int \ int" where "k mod l = (if l = 0 then k else if sgn k = sgn l then sgn l * int (nat \k\ mod nat \l\) else sgn l * (\l\ * of_bool (\ l dvd k) - int (nat \k\ mod nat \l\)))" lemma modulo_int_unfold: "(sgn k * int m) mod (sgn l * int n) = (if sgn l = 0 \ sgn k = 0 \ n = 0 then sgn k * int m else if sgn k = sgn l then sgn l * int (m mod n) else sgn l * (int (n * of_bool (\ n dvd m)) - int (m mod n)))" by (auto simp add: modulo_int_def sgn_0_0 sgn_1_pos sgn_mult abs_mult nat_mult_distrib) instance proof fix k l :: int obtain n m and s t where "k = sgn s * int n" and "l = sgn t * int m" by (blast intro: int_sgnE elim: that) then show "k div l * l + k mod l = k" by (auto simp add: divide_int_unfold modulo_int_unfold algebra_simps dest!: sgn_not_eq_imp) (simp_all add: of_nat_mult [symmetric] of_nat_add [symmetric] distrib_left [symmetric] minus_mult_right del: of_nat_mult minus_mult_right [symmetric]) qed end instantiation int :: unique_euclidean_ring begin definition euclidean_size_int :: "int \ nat" where [simp]: "euclidean_size_int = (nat \ abs :: int \ nat)" definition division_segment_int :: "int \ int" where "division_segment_int k = (if k \ 0 then 1 else - 1)" lemma division_segment_eq_sgn: "division_segment k = sgn k" if "k \ 0" for k :: int using that by (simp add: division_segment_int_def) lemma abs_division_segment [simp]: "\division_segment k\ = 1" for k :: int by (simp add: division_segment_int_def) lemma abs_mod_less: "\k mod l\ < \l\" if "l \ 0" for k l :: int proof - obtain n m and s t where "k = sgn s * int n" and "l = sgn t * int m" by (blast intro: int_sgnE elim: that) with that show ?thesis by (simp add: modulo_int_unfold sgn_0_0 sgn_1_pos sgn_1_neg abs_mult mod_greater_zero_iff_not_dvd) qed lemma sgn_mod: "sgn (k mod l) = sgn l" if "l \ 0" "\ l dvd k" for k l :: int proof - obtain n m and s t where "k = sgn s * int n" and "l = sgn t * int m" by (blast intro: int_sgnE elim: that) with that show ?thesis by (simp add: modulo_int_unfold sgn_0_0 sgn_1_pos sgn_1_neg sgn_mult mod_eq_0_iff_dvd) qed instance proof fix k l :: int show "division_segment (k mod l) = division_segment l" if "l \ 0" and "\ l dvd k" using that by (simp add: division_segment_eq_sgn dvd_eq_mod_eq_0 sgn_mod) next fix l q r :: int obtain n m and s t where l: "l = sgn s * int n" and q: "q = sgn t * int m" by (blast intro: int_sgnE elim: that) assume \l \ 0\ with l have "s \ 0" and "n > 0" by (simp_all add: sgn_0_0) assume "division_segment r = division_segment l" moreover have "r = sgn r * \r\" by (simp add: sgn_mult_abs) moreover define u where "u = nat \r\" ultimately have "r = sgn l * int u" using division_segment_eq_sgn \l \ 0\ by (cases "r = 0") simp_all with l \n > 0\ have r: "r = sgn s * int u" by (simp add: sgn_mult) assume "euclidean_size r < euclidean_size l" with l r \s \ 0\ have "u < n" by (simp add: abs_mult) show "(q * l + r) div l = q" proof (cases "q = 0 \ r = 0") case True then show ?thesis proof assume "q = 0" then show ?thesis using l r \u < n\ by (simp add: divide_int_unfold) next assume "r = 0" from \r = 0\ have *: "q * l + r = sgn (t * s) * int (n * m)" using q l by (simp add: ac_simps sgn_mult) from \s \ 0\ \n > 0\ show ?thesis by (simp only: *, simp only: q l divide_int_unfold) (auto simp add: sgn_mult sgn_0_0 sgn_1_pos) qed next case False with q r have "t \ 0" and "m > 0" and "s \ 0" and "u > 0" by (simp_all add: sgn_0_0) moreover from \0 < m\ \u < n\ have "u \ m * n" using mult_le_less_imp_less [of 1 m u n] by simp ultimately have *: "q * l + r = sgn (s * t) * int (if t < 0 then m * n - u else m * n + u)" using l q r by (simp add: sgn_mult algebra_simps of_nat_diff) have "(m * n - u) div n = m - 1" if "u > 0" using \0 < m\ \u < n\ that by (auto intro: div_nat_eqI simp add: algebra_simps) moreover have "n dvd m * n - u \ n dvd u" using \u \ m * n\ dvd_diffD1 [of n "m * n" u] by auto ultimately show ?thesis using \s \ 0\ \m > 0\ \u > 0\ \u < n\ \u \ m * n\ by (simp only: *, simp only: l q divide_int_unfold) (auto simp add: sgn_mult sgn_0_0 sgn_1_pos algebra_simps dest: dvd_imp_le) qed qed (use mult_le_mono2 [of 1] in \auto simp add: division_segment_int_def not_le zero_less_mult_iff mult_less_0_iff abs_mult sgn_mult abs_mod_less sgn_mod nat_mult_distrib\) end lemma pos_mod_bound [simp]: "k mod l < l" if "l > 0" for k l :: int proof - obtain m and s where "k = sgn s * int m" by (rule int_sgnE) moreover from that obtain n where "l = sgn 1 * int n" by (cases l) simp_all moreover from this that have "n > 0" by simp ultimately show ?thesis by (simp only: modulo_int_unfold) (simp add: mod_greater_zero_iff_not_dvd) qed lemma neg_mod_bound [simp]: "l < k mod l" if "l < 0" for k l :: int proof - obtain m and s where "k = sgn s * int m" by (rule int_sgnE) moreover from that obtain q where "l = sgn (- 1) * int (Suc q)" by (cases l) simp_all moreover define n where "n = Suc q" then have "Suc q = n" by simp ultimately show ?thesis by (simp only: modulo_int_unfold) (simp add: mod_greater_zero_iff_not_dvd) qed lemma pos_mod_sign [simp]: "0 \ k mod l" if "l > 0" for k l :: int proof - obtain m and s where "k = sgn s * int m" by (rule int_sgnE) moreover from that obtain n where "l = sgn 1 * int n" by (cases l) auto moreover from this that have "n > 0" by simp ultimately show ?thesis by (simp only: modulo_int_unfold) simp qed lemma neg_mod_sign [simp]: "k mod l \ 0" if "l < 0" for k l :: int proof - obtain m and s where "k = sgn s * int m" by (rule int_sgnE) moreover from that obtain q where "l = sgn (- 1) * int (Suc q)" by (cases l) simp_all moreover define n where "n = Suc q" then have "Suc q = n" by simp ultimately show ?thesis by (simp only: modulo_int_unfold) simp qed subsection \Special case: euclidean rings containing the natural numbers\ class unique_euclidean_semiring_with_nat = semidom + semiring_char_0 + unique_euclidean_semiring + assumes of_nat_div: "of_nat (m div n) = of_nat m div of_nat n" and division_segment_of_nat [simp]: "division_segment (of_nat n) = 1" and division_segment_euclidean_size [simp]: "division_segment a * of_nat (euclidean_size a) = a" begin lemma division_segment_eq_iff: "a = b" if "division_segment a = division_segment b" and "euclidean_size a = euclidean_size b" using that division_segment_euclidean_size [of a] by simp lemma euclidean_size_of_nat [simp]: "euclidean_size (of_nat n) = n" proof - have "division_segment (of_nat n) * of_nat (euclidean_size (of_nat n)) = of_nat n" by (fact division_segment_euclidean_size) then show ?thesis by simp qed lemma of_nat_euclidean_size: "of_nat (euclidean_size a) = a div division_segment a" proof - have "of_nat (euclidean_size a) = division_segment a * of_nat (euclidean_size a) div division_segment a" by (subst nonzero_mult_div_cancel_left) simp_all also have "\ = a div division_segment a" by simp finally show ?thesis . qed lemma division_segment_1 [simp]: "division_segment 1 = 1" using division_segment_of_nat [of 1] by simp lemma division_segment_numeral [simp]: "division_segment (numeral k) = 1" using division_segment_of_nat [of "numeral k"] by simp lemma euclidean_size_1 [simp]: "euclidean_size 1 = 1" using euclidean_size_of_nat [of 1] by simp lemma euclidean_size_numeral [simp]: "euclidean_size (numeral k) = numeral k" using euclidean_size_of_nat [of "numeral k"] by simp lemma of_nat_dvd_iff: "of_nat m dvd of_nat n \ m dvd n" (is "?P \ ?Q") proof (cases "m = 0") case True then show ?thesis by simp next case False show ?thesis proof assume ?Q then show ?P by auto next assume ?P with False have "of_nat n = of_nat n div of_nat m * of_nat m" by simp then have "of_nat n = of_nat (n div m * m)" by (simp add: of_nat_div) then have "n = n div m * m" by (simp only: of_nat_eq_iff) then have "n = m * (n div m)" by (simp add: ac_simps) then show ?Q .. qed qed lemma of_nat_mod: "of_nat (m mod n) = of_nat m mod of_nat n" proof - have "of_nat m div of_nat n * of_nat n + of_nat m mod of_nat n = of_nat m" by (simp add: div_mult_mod_eq) also have "of_nat m = of_nat (m div n * n + m mod n)" by simp finally show ?thesis by (simp only: of_nat_div of_nat_mult of_nat_add) simp qed lemma one_div_two_eq_zero [simp]: "1 div 2 = 0" proof - from of_nat_div [symmetric] have "of_nat 1 div of_nat 2 = of_nat 0" by (simp only:) simp then show ?thesis by simp qed lemma one_mod_two_eq_one [simp]: "1 mod 2 = 1" proof - from of_nat_mod [symmetric] have "of_nat 1 mod of_nat 2 = of_nat 1" by (simp only:) simp then show ?thesis by simp qed lemma one_mod_2_pow_eq [simp]: "1 mod (2 ^ n) = of_bool (n > 0)" proof - have "1 mod (2 ^ n) = of_nat (1 mod (2 ^ n))" using of_nat_mod [of 1 "2 ^ n"] by simp also have "\ = of_bool (n > 0)" by simp finally show ?thesis . qed lemma one_div_2_pow_eq [simp]: "1 div (2 ^ n) = of_bool (n = 0)" using div_mult_mod_eq [of 1 "2 ^ n"] by auto lemma div_mult2_eq': "a div (of_nat m * of_nat n) = a div of_nat m div of_nat n" proof (cases a "of_nat m * of_nat n" rule: divmod_cases) case (divides q) then show ?thesis using nonzero_mult_div_cancel_right [of "of_nat m" "q * of_nat n"] by (simp add: ac_simps) next case (remainder q r) then have "division_segment r = 1" using division_segment_of_nat [of "m * n"] by simp with division_segment_euclidean_size [of r] have "of_nat (euclidean_size r) = r" by simp have "a mod (of_nat m * of_nat n) div (of_nat m * of_nat n) = 0" by simp with remainder(6) have "r div (of_nat m * of_nat n) = 0" by simp with \of_nat (euclidean_size r) = r\ have "of_nat (euclidean_size r) div (of_nat m * of_nat n) = 0" by simp then have "of_nat (euclidean_size r div (m * n)) = 0" by (simp add: of_nat_div) then have "of_nat (euclidean_size r div m div n) = 0" by (simp add: div_mult2_eq) with \of_nat (euclidean_size r) = r\ have "r div of_nat m div of_nat n = 0" by (simp add: of_nat_div) with remainder(1) have "q = (r div of_nat m + q * of_nat n * of_nat m div of_nat m) div of_nat n" by simp with remainder(5) remainder(7) show ?thesis using div_plus_div_distrib_dvd_right [of "of_nat m" "q * (of_nat m * of_nat n)" r] by (simp add: ac_simps) next case by0 then show ?thesis by auto qed lemma mod_mult2_eq': "a mod (of_nat m * of_nat n) = of_nat m * (a div of_nat m mod of_nat n) + a mod of_nat m" proof - have "a div (of_nat m * of_nat n) * (of_nat m * of_nat n) + a mod (of_nat m * of_nat n) = a div of_nat m div of_nat n * of_nat n * of_nat m + (a div of_nat m mod of_nat n * of_nat m + a mod of_nat m)" by (simp add: combine_common_factor div_mult_mod_eq) moreover have "a div of_nat m div of_nat n * of_nat n * of_nat m = of_nat n * of_nat m * (a div of_nat m div of_nat n)" by (simp add: ac_simps) ultimately show ?thesis by (simp add: div_mult2_eq' mult_commute) qed lemma div_mult2_numeral_eq: "a div numeral k div numeral l = a div numeral (k * l)" (is "?A = ?B") proof - have "?A = a div of_nat (numeral k) div of_nat (numeral l)" by simp also have "\ = a div (of_nat (numeral k) * of_nat (numeral l))" by (fact div_mult2_eq' [symmetric]) also have "\ = ?B" by simp finally show ?thesis . qed lemma numeral_Bit0_div_2: "numeral (num.Bit0 n) div 2 = numeral n" proof - have "numeral (num.Bit0 n) = numeral n + numeral n" by (simp only: numeral.simps) also have "\ = numeral n * 2" by (simp add: mult_2_right) finally have "numeral (num.Bit0 n) div 2 = numeral n * 2 div 2" by simp also have "\ = numeral n" by (rule nonzero_mult_div_cancel_right) simp finally show ?thesis . qed lemma numeral_Bit1_div_2: "numeral (num.Bit1 n) div 2 = numeral n" proof - have "numeral (num.Bit1 n) = numeral n + numeral n + 1" by (simp only: numeral.simps) also have "\ = numeral n * 2 + 1" by (simp add: mult_2_right) finally have "numeral (num.Bit1 n) div 2 = (numeral n * 2 + 1) div 2" by simp also have "\ = numeral n * 2 div 2 + 1 div 2" using dvd_triv_right by (rule div_plus_div_distrib_dvd_left) also have "\ = numeral n * 2 div 2" by simp also have "\ = numeral n" by (rule nonzero_mult_div_cancel_right) simp finally show ?thesis . qed lemma exp_mod_exp: \2 ^ m mod 2 ^ n = of_bool (m < n) * 2 ^ m\ proof - have \(2::nat) ^ m mod 2 ^ n = of_bool (m < n) * 2 ^ m\ (is \?lhs = ?rhs\) by (auto simp add: not_less monoid_mult_class.power_add dest!: le_Suc_ex) then have \of_nat ?lhs = of_nat ?rhs\ by simp then show ?thesis by (simp add: of_nat_mod) qed -lemma range_mod_exp: +lemma mask_mod_exp: \(2 ^ n - 1) mod 2 ^ m = 2 ^ min m n - 1\ proof - have \(2 ^ n - 1) mod 2 ^ m = 2 ^ min m n - (1::nat)\ (is \?lhs = ?rhs\) proof (cases \n \ m\) case True then show ?thesis by (simp add: Suc_le_lessD min.absorb2) next case False then have \m < n\ by simp then obtain q where n: \n = Suc q + m\ by (auto dest: less_imp_Suc_add) then have \min m n = m\ by simp moreover have \(2::nat) ^ m \ 2 * 2 ^ q * 2 ^ m\ using mult_le_mono1 [of 1 \2 * 2 ^ q\ \2 ^ m\] by simp with n have \2 ^ n - 1 = (2 ^ Suc q - 1) * 2 ^ m + (2 ^ m - (1::nat))\ by (simp add: monoid_mult_class.power_add algebra_simps) ultimately show ?thesis by (simp only: euclidean_semiring_cancel_class.mod_mult_self3) simp qed then have \of_nat ?lhs = of_nat ?rhs\ by simp then show ?thesis by (simp add: of_nat_mod of_nat_diff) qed end class unique_euclidean_ring_with_nat = ring + unique_euclidean_semiring_with_nat instance nat :: unique_euclidean_semiring_with_nat by standard (simp_all add: dvd_eq_mod_eq_0) instance int :: unique_euclidean_ring_with_nat by standard (simp_all add: dvd_eq_mod_eq_0 divide_int_def division_segment_int_def) subsection \Code generation\ code_identifier code_module Euclidean_Division \ (SML) Arith and (OCaml) Arith and (Haskell) Arith end diff --git a/src/HOL/Parity.thy b/src/HOL/Parity.thy --- a/src/HOL/Parity.thy +++ b/src/HOL/Parity.thy @@ -1,1282 +1,1397 @@ (* Title: HOL/Parity.thy Author: Jeremy Avigad Author: Jacques D. Fleuriot *) section \Parity in rings and semirings\ theory Parity imports Euclidean_Division begin subsection \Ring structures with parity and \even\/\odd\ predicates\ class semiring_parity = comm_semiring_1 + semiring_modulo + assumes even_iff_mod_2_eq_zero: "2 dvd a \ a mod 2 = 0" and odd_iff_mod_2_eq_one: "\ 2 dvd a \ a mod 2 = 1" and odd_one [simp]: "\ 2 dvd 1" begin abbreviation even :: "'a \ bool" where "even a \ 2 dvd a" abbreviation odd :: "'a \ bool" where "odd a \ \ 2 dvd a" lemma parity_cases [case_names even odd]: assumes "even a \ a mod 2 = 0 \ P" assumes "odd a \ a mod 2 = 1 \ P" shows P using assms by (cases "even a") (simp_all add: even_iff_mod_2_eq_zero [symmetric] odd_iff_mod_2_eq_one [symmetric]) lemma odd_of_bool_self [simp]: \odd (of_bool p) \ p\ by (cases p) simp_all lemma not_mod_2_eq_0_eq_1 [simp]: "a mod 2 \ 0 \ a mod 2 = 1" by (cases a rule: parity_cases) simp_all lemma not_mod_2_eq_1_eq_0 [simp]: "a mod 2 \ 1 \ a mod 2 = 0" by (cases a rule: parity_cases) simp_all lemma mod2_eq_if: "a mod 2 = (if 2 dvd a then 0 else 1)" by (simp add: even_iff_mod_2_eq_zero odd_iff_mod_2_eq_one) lemma evenE [elim?]: assumes "even a" obtains b where "a = 2 * b" using assms by (rule dvdE) lemma oddE [elim?]: assumes "odd a" obtains b where "a = 2 * b + 1" proof - have "a = 2 * (a div 2) + a mod 2" by (simp add: mult_div_mod_eq) with assms have "a = 2 * (a div 2) + 1" by (simp add: odd_iff_mod_2_eq_one) then show ?thesis .. qed lemma mod_2_eq_odd: "a mod 2 = of_bool (odd a)" by (auto elim: oddE simp add: even_iff_mod_2_eq_zero) lemma of_bool_odd_eq_mod_2: "of_bool (odd a) = a mod 2" by (simp add: mod_2_eq_odd) lemma even_zero [simp]: "even 0" by (fact dvd_0_right) lemma odd_even_add: "even (a + b)" if "odd a" and "odd b" proof - from that obtain c d where "a = 2 * c + 1" and "b = 2 * d + 1" by (blast elim: oddE) then have "a + b = 2 * c + 2 * d + (1 + 1)" by (simp only: ac_simps) also have "\ = 2 * (c + d + 1)" by (simp add: algebra_simps) finally show ?thesis .. qed lemma even_add [simp]: "even (a + b) \ (even a \ even b)" by (auto simp add: dvd_add_right_iff dvd_add_left_iff odd_even_add) lemma odd_add [simp]: "odd (a + b) \ \ (odd a \ odd b)" by simp lemma even_plus_one_iff [simp]: "even (a + 1) \ odd a" by (auto simp add: dvd_add_right_iff intro: odd_even_add) lemma even_mult_iff [simp]: "even (a * b) \ even a \ even b" (is "?P \ ?Q") proof assume ?Q then show ?P by auto next assume ?P show ?Q proof (rule ccontr) assume "\ (even a \ even b)" then have "odd a" and "odd b" by auto then obtain r s where "a = 2 * r + 1" and "b = 2 * s + 1" by (blast elim: oddE) then have "a * b = (2 * r + 1) * (2 * s + 1)" by simp also have "\ = 2 * (2 * r * s + r + s) + 1" by (simp add: algebra_simps) finally have "odd (a * b)" by simp with \?P\ show False by auto qed qed lemma even_numeral [simp]: "even (numeral (Num.Bit0 n))" proof - have "even (2 * numeral n)" unfolding even_mult_iff by simp then have "even (numeral n + numeral n)" unfolding mult_2 . then show ?thesis unfolding numeral.simps . qed lemma odd_numeral [simp]: "odd (numeral (Num.Bit1 n))" proof assume "even (numeral (num.Bit1 n))" then have "even (numeral n + numeral n + 1)" unfolding numeral.simps . then have "even (2 * numeral n + 1)" unfolding mult_2 . then have "2 dvd numeral n * 2 + 1" by (simp add: ac_simps) then have "2 dvd 1" using dvd_add_times_triv_left_iff [of 2 "numeral n" 1] by simp then show False by simp qed lemma even_power [simp]: "even (a ^ n) \ even a \ n > 0" by (induct n) auto +lemma mask_eq_sum_exp: + \2 ^ n - 1 = (\m\{q. q < n}. 2 ^ m)\ +proof - + have *: \{q. q < Suc m} = insert m {q. q < m}\ for m + by auto + have \2 ^ n = (\m\{q. q < n}. 2 ^ m) + 1\ + by (induction n) (simp_all add: ac_simps mult_2 *) + then have \2 ^ n - 1 = (\m\{q. q < n}. 2 ^ m) + 1 - 1\ + by simp + then show ?thesis + by simp +qed + end class ring_parity = ring + semiring_parity begin subclass comm_ring_1 .. lemma even_minus: "even (- a) \ even a" by (fact dvd_minus_iff) lemma even_diff [simp]: "even (a - b) \ even (a + b)" using even_add [of a "- b"] by simp end subsection \Special case: euclidean rings containing the natural numbers\ context unique_euclidean_semiring_with_nat begin subclass semiring_parity proof show "2 dvd a \ a mod 2 = 0" for a by (fact dvd_eq_mod_eq_0) show "\ 2 dvd a \ a mod 2 = 1" for a proof assume "a mod 2 = 1" then show "\ 2 dvd a" by auto next assume "\ 2 dvd a" have eucl: "euclidean_size (a mod 2) = 1" proof (rule order_antisym) show "euclidean_size (a mod 2) \ 1" using mod_size_less [of 2 a] by simp show "1 \ euclidean_size (a mod 2)" using \\ 2 dvd a\ by (simp add: Suc_le_eq dvd_eq_mod_eq_0) qed from \\ 2 dvd a\ have "\ of_nat 2 dvd division_segment a * of_nat (euclidean_size a)" by simp then have "\ of_nat 2 dvd of_nat (euclidean_size a)" by (auto simp only: dvd_mult_unit_iff' is_unit_division_segment) then have "\ 2 dvd euclidean_size a" using of_nat_dvd_iff [of 2] by simp then have "euclidean_size a mod 2 = 1" by (simp add: semidom_modulo_class.dvd_eq_mod_eq_0) then have "of_nat (euclidean_size a mod 2) = of_nat 1" by simp then have "of_nat (euclidean_size a) mod 2 = 1" by (simp add: of_nat_mod) from \\ 2 dvd a\ eucl show "a mod 2 = 1" by (auto intro: division_segment_eq_iff simp add: division_segment_mod) qed show "\ is_unit 2" proof (rule notI) assume "is_unit 2" then have "of_nat 2 dvd of_nat 1" by simp then have "is_unit (2::nat)" by (simp only: of_nat_dvd_iff) then show False by simp qed qed lemma even_of_nat [simp]: "even (of_nat a) \ even a" proof - have "even (of_nat a) \ of_nat 2 dvd of_nat a" by simp also have "\ \ even a" by (simp only: of_nat_dvd_iff) finally show ?thesis . qed lemma even_succ_div_two [simp]: "even a \ (a + 1) div 2 = a div 2" by (cases "a = 0") (auto elim!: evenE dest: mult_not_zero) lemma odd_succ_div_two [simp]: "odd a \ (a + 1) div 2 = a div 2 + 1" by (auto elim!: oddE simp add: add.assoc) lemma even_two_times_div_two: "even a \ 2 * (a div 2) = a" by (fact dvd_mult_div_cancel) lemma odd_two_times_div_two_succ [simp]: "odd a \ 2 * (a div 2) + 1 = a" using mult_div_mod_eq [of 2 a] by (simp add: even_iff_mod_2_eq_zero) lemma coprime_left_2_iff_odd [simp]: "coprime 2 a \ odd a" proof assume "odd a" show "coprime 2 a" proof (rule coprimeI) fix b assume "b dvd 2" "b dvd a" then have "b dvd a mod 2" by (auto intro: dvd_mod) with \odd a\ show "is_unit b" by (simp add: mod_2_eq_odd) qed next assume "coprime 2 a" show "odd a" proof (rule notI) assume "even a" then obtain b where "a = 2 * b" .. with \coprime 2 a\ have "coprime 2 (2 * b)" by simp moreover have "\ coprime 2 (2 * b)" by (rule not_coprimeI [of 2]) simp_all ultimately show False by blast qed qed lemma coprime_right_2_iff_odd [simp]: "coprime a 2 \ odd a" using coprime_left_2_iff_odd [of a] by (simp add: ac_simps) end context unique_euclidean_ring_with_nat begin subclass ring_parity .. lemma minus_1_mod_2_eq [simp]: "- 1 mod 2 = 1" by (simp add: mod_2_eq_odd) lemma minus_1_div_2_eq [simp]: "- 1 div 2 = - 1" proof - from div_mult_mod_eq [of "- 1" 2] have "- 1 div 2 * 2 = - 1 * 2" using add_implies_diff by fastforce then show ?thesis using mult_right_cancel [of 2 "- 1 div 2" "- 1"] by simp qed end subsection \Instance for \<^typ>\nat\\ instance nat :: unique_euclidean_semiring_with_nat by standard (simp_all add: dvd_eq_mod_eq_0) lemma even_Suc_Suc_iff [simp]: "even (Suc (Suc n)) \ even n" using dvd_add_triv_right_iff [of 2 n] by simp lemma even_Suc [simp]: "even (Suc n) \ odd n" using even_plus_one_iff [of n] by simp lemma even_diff_nat [simp]: "even (m - n) \ m < n \ even (m + n)" for m n :: nat proof (cases "n \ m") case True then have "m - n + n * 2 = m + n" by (simp add: mult_2_right) moreover have "even (m - n) \ even (m - n + n * 2)" by simp ultimately have "even (m - n) \ even (m + n)" by (simp only:) then show ?thesis by auto next case False then show ?thesis by simp qed lemma odd_pos: "odd n \ 0 < n" for n :: nat by (auto elim: oddE) lemma Suc_double_not_eq_double: "Suc (2 * m) \ 2 * n" proof assume "Suc (2 * m) = 2 * n" moreover have "odd (Suc (2 * m))" and "even (2 * n)" by simp_all ultimately show False by simp qed lemma double_not_eq_Suc_double: "2 * m \ Suc (2 * n)" using Suc_double_not_eq_double [of n m] by simp lemma odd_Suc_minus_one [simp]: "odd n \ Suc (n - Suc 0) = n" by (auto elim: oddE) lemma even_Suc_div_two [simp]: "even n \ Suc n div 2 = n div 2" using even_succ_div_two [of n] by simp lemma odd_Suc_div_two [simp]: "odd n \ Suc n div 2 = Suc (n div 2)" using odd_succ_div_two [of n] by simp lemma odd_two_times_div_two_nat [simp]: assumes "odd n" shows "2 * (n div 2) = n - (1 :: nat)" proof - from assms have "2 * (n div 2) + 1 = n" by (rule odd_two_times_div_two_succ) then have "Suc (2 * (n div 2)) - 1 = n - 1" by simp then show ?thesis by simp qed lemma not_mod2_eq_Suc_0_eq_0 [simp]: "n mod 2 \ Suc 0 \ n mod 2 = 0" using not_mod_2_eq_1_eq_0 [of n] by simp lemma odd_card_imp_not_empty: \A \ {}\ if \odd (card A)\ using that by auto lemma nat_induct2 [case_names 0 1 step]: assumes "P 0" "P 1" and step: "\n::nat. P n \ P (n + 2)" shows "P n" proof (induct n rule: less_induct) case (less n) show ?case proof (cases "n < Suc (Suc 0)") case True then show ?thesis using assms by (auto simp: less_Suc_eq) next case False then obtain k where k: "n = Suc (Suc k)" by (force simp: not_less nat_le_iff_add) then have "keven (sum f A) \ even (card {a\A. odd (f a)})\ if \finite A\ +using that proof (induction A) + case empty + then show ?case + by simp +next + case (insert a A) + moreover have \{b \ insert a A. odd (f b)} = (if odd (f a) then {a} else {}) \ {b \ A. odd (f b)}\ + by auto + ultimately show ?case + by simp +qed + +lemma even_prod_iff: + \even (prod f A) \ (\a\A. even (f a))\ if \finite A\ + using that by (induction A) simp_all + +lemma even_mask_iff [simp]: + \even (2 ^ n - 1) \ n = 0\ +proof (cases \n = 0\) + case True + then show ?thesis + by simp +next + case False + then have \{a. a = 0 \ a < n} = {0}\ + by auto + then show ?thesis + by (auto simp add: mask_eq_sum_exp even_sum_iff) +qed + +end + subsection \Parity and powers\ context ring_1 begin lemma power_minus_even [simp]: "even n \ (- a) ^ n = a ^ n" by (auto elim: evenE) lemma power_minus_odd [simp]: "odd n \ (- a) ^ n = - (a ^ n)" by (auto elim: oddE) lemma uminus_power_if: "(- a) ^ n = (if even n then a ^ n else - (a ^ n))" by auto lemma neg_one_even_power [simp]: "even n \ (- 1) ^ n = 1" by simp lemma neg_one_odd_power [simp]: "odd n \ (- 1) ^ n = - 1" by simp lemma neg_one_power_add_eq_neg_one_power_diff: "k \ n \ (- 1) ^ (n + k) = (- 1) ^ (n - k)" by (cases "even (n + k)") auto lemma minus_one_power_iff: "(- 1) ^ n = (if even n then 1 else - 1)" by (induct n) auto end context linordered_idom begin lemma zero_le_even_power: "even n \ 0 \ a ^ n" by (auto elim: evenE) lemma zero_le_odd_power: "odd n \ 0 \ a ^ n \ 0 \ a" by (auto simp add: power_even_eq zero_le_mult_iff elim: oddE) lemma zero_le_power_eq: "0 \ a ^ n \ even n \ odd n \ 0 \ a" by (auto simp add: zero_le_even_power zero_le_odd_power) lemma zero_less_power_eq: "0 < a ^ n \ n = 0 \ even n \ a \ 0 \ odd n \ 0 < a" proof - have [simp]: "0 = a ^ n \ a = 0 \ n > 0" unfolding power_eq_0_iff [of a n, symmetric] by blast show ?thesis unfolding less_le zero_le_power_eq by auto qed lemma power_less_zero_eq [simp]: "a ^ n < 0 \ odd n \ a < 0" unfolding not_le [symmetric] zero_le_power_eq by auto lemma power_le_zero_eq: "a ^ n \ 0 \ n > 0 \ (odd n \ a \ 0 \ even n \ a = 0)" unfolding not_less [symmetric] zero_less_power_eq by auto lemma power_even_abs: "even n \ \a\ ^ n = a ^ n" using power_abs [of a n] by (simp add: zero_le_even_power) lemma power_mono_even: assumes "even n" and "\a\ \ \b\" shows "a ^ n \ b ^ n" proof - have "0 \ \a\" by auto with \\a\ \ \b\\ have "\a\ ^ n \ \b\ ^ n" by (rule power_mono) with \even n\ show ?thesis by (simp add: power_even_abs) qed lemma power_mono_odd: assumes "odd n" and "a \ b" shows "a ^ n \ b ^ n" proof (cases "b < 0") case True with \a \ b\ have "- b \ - a" and "0 \ - b" by auto then have "(- b) ^ n \ (- a) ^ n" by (rule power_mono) with \odd n\ show ?thesis by simp next case False then have "0 \ b" by auto show ?thesis proof (cases "a < 0") case True then have "n \ 0" and "a \ 0" using \odd n\ [THEN odd_pos] by auto then have "a ^ n \ 0" unfolding power_le_zero_eq using \odd n\ by auto moreover from \0 \ b\ have "0 \ b ^ n" by auto ultimately show ?thesis by auto next case False then have "0 \ a" by auto with \a \ b\ show ?thesis using power_mono by auto qed qed text \Simplify, when the exponent is a numeral\ lemma zero_le_power_eq_numeral [simp]: "0 \ a ^ numeral w \ even (numeral w :: nat) \ odd (numeral w :: nat) \ 0 \ a" by (fact zero_le_power_eq) lemma zero_less_power_eq_numeral [simp]: "0 < a ^ numeral w \ numeral w = (0 :: nat) \ even (numeral w :: nat) \ a \ 0 \ odd (numeral w :: nat) \ 0 < a" by (fact zero_less_power_eq) lemma power_le_zero_eq_numeral [simp]: "a ^ numeral w \ 0 \ (0 :: nat) < numeral w \ (odd (numeral w :: nat) \ a \ 0 \ even (numeral w :: nat) \ a = 0)" by (fact power_le_zero_eq) lemma power_less_zero_eq_numeral [simp]: "a ^ numeral w < 0 \ odd (numeral w :: nat) \ a < 0" by (fact power_less_zero_eq) lemma power_even_abs_numeral [simp]: "even (numeral w :: nat) \ \a\ ^ numeral w = a ^ numeral w" by (fact power_even_abs) end subsection \Instance for \<^typ>\int\\ lemma even_diff_iff: "even (k - l) \ even (k + l)" for k l :: int by (fact even_diff) lemma even_abs_add_iff: "even (\k\ + l) \ even (k + l)" for k l :: int by simp lemma even_add_abs_iff: "even (k + \l\) \ even (k + l)" for k l :: int by simp lemma even_nat_iff: "0 \ k \ even (nat k) \ even k" by (simp add: even_of_nat [of "nat k", where ?'a = int, symmetric]) lemma zdiv_zmult2_eq: \a div (b * c) = (a div b) div c\ if \c \ 0\ for a b c :: int proof (cases \b \ 0\) case True with that show ?thesis using div_mult2_eq' [of a \nat b\ \nat c\] by simp next case False with that show ?thesis using div_mult2_eq' [of \- a\ \nat (- b)\ \nat c\] by simp qed lemma zmod_zmult2_eq: \a mod (b * c) = b * (a div b mod c) + a mod b\ if \c \ 0\ for a b c :: int proof (cases \b \ 0\) case True with that show ?thesis using mod_mult2_eq' [of a \nat b\ \nat c\] by simp next case False with that show ?thesis using mod_mult2_eq' [of \- a\ \nat (- b)\ \nat c\] by simp qed subsection \Abstract bit structures\ class semiring_bits = semiring_parity + assumes bits_induct [case_names stable rec]: \(\a. a div 2 = a \ P a) \ (\a b. P a \ (of_bool b + 2 * a) div 2 = a \ P (of_bool b + 2 * a)) \ P a\ assumes bits_div_0 [simp]: \0 div a = 0\ and bits_div_by_1 [simp]: \a div 1 = a\ and bits_mod_div_trivial [simp]: \a mod b div b = 0\ and even_succ_div_2 [simp]: \even a \ (1 + a) div 2 = a div 2\ and exp_div_exp_eq: \2 ^ m div 2 ^ n = of_bool (2 ^ m \ 0 \ m \ n) * 2 ^ (m - n)\ and div_exp_eq: \a div 2 ^ m div 2 ^ n = a div 2 ^ (m + n)\ and mod_exp_eq: \a mod 2 ^ m mod 2 ^ n = a mod 2 ^ min m n\ and mult_exp_mod_exp_eq: \m \ n \ (a * 2 ^ m) mod (2 ^ n) = (a mod 2 ^ (n - m)) * 2 ^ m\ and div_exp_mod_exp_eq: \a div 2 ^ n mod 2 ^ m = a mod (2 ^ (n + m)) div 2 ^ n\ begin lemma bits_div_by_0 [simp]: \a div 0 = 0\ by (metis add_cancel_right_right bits_mod_div_trivial mod_mult_div_eq mult_not_zero) lemma bits_1_div_2 [simp]: \1 div 2 = 0\ using even_succ_div_2 [of 0] by simp lemma bits_1_div_exp [simp]: \1 div 2 ^ n = of_bool (n = 0)\ using div_exp_eq [of 1 1] by (cases n) simp_all lemma even_succ_div_exp [simp]: \(1 + a) div 2 ^ n = a div 2 ^ n\ if \even a\ and \n > 0\ proof (cases n) case 0 with that show ?thesis by simp next case (Suc n) with \even a\ have \(1 + a) div 2 ^ Suc n = a div 2 ^ Suc n\ proof (induction n) case 0 then show ?case by simp next case (Suc n) then show ?case using div_exp_eq [of _ 1 \Suc n\, symmetric] by simp qed with Suc show ?thesis by simp qed lemma even_succ_mod_exp [simp]: \(1 + a) mod 2 ^ n = 1 + (a mod 2 ^ n)\ if \even a\ and \n > 0\ using div_mult_mod_eq [of \1 + a\ \2 ^ n\] that apply simp by (metis local.add.left_commute local.add_left_cancel local.div_mult_mod_eq) lemma bits_mod_by_1 [simp]: \a mod 1 = 0\ using div_mult_mod_eq [of a 1] by simp lemma bits_mod_0 [simp]: \0 mod a = 0\ using div_mult_mod_eq [of 0 a] by simp lemma bits_one_mod_two_eq_one [simp]: \1 mod 2 = 1\ by (simp add: mod2_eq_if) definition bit :: \'a \ nat \ bool\ where \bit a n \ odd (a div 2 ^ n)\ lemma bit_0 [simp]: \bit a 0 \ odd a\ by (simp add: bit_def) lemma bit_Suc [simp]: \bit a (Suc n) \ bit (a div 2) n\ using div_exp_eq [of a 1 n] by (simp add: bit_def) lemma bit_0_eq [simp]: \bit 0 = bot\ by (simp add: fun_eq_iff bit_def) context fixes a assumes stable: \a div 2 = a\ begin lemma bits_stable_imp_add_self: \a + a mod 2 = 0\ proof - have \a div 2 * 2 + a mod 2 = a\ by (fact div_mult_mod_eq) then have \a * 2 + a mod 2 = a\ by (simp add: stable) then show ?thesis by (simp add: mult_2_right ac_simps) qed lemma stable_imp_bit_iff_odd: \bit a n \ odd a\ by (induction n) (simp_all add: stable) end lemma bit_iff_idd_imp_stable: \a div 2 = a\ if \\n. bit a n \ odd a\ using that proof (induction a rule: bits_induct) case (stable a) then show ?case by simp next case (rec a b) from rec.prems [of 1] have [simp]: \b = odd a\ by (simp add: rec.hyps) from rec.hyps have hyp: \(of_bool (odd a) + 2 * a) div 2 = a\ by simp have \bit a n \ odd a\ for n using rec.prems [of \Suc n\] by (simp add: hyp) then have \a div 2 = a\ by (rule rec.IH) then have \of_bool (odd a) + 2 * a = 2 * (a div 2) + of_bool (odd a)\ by (simp add: ac_simps) also have \\ = a\ using mult_div_mod_eq [of 2 a] by (simp add: of_bool_odd_eq_mod_2) finally show ?case using \a div 2 = a\ by (simp add: hyp) qed lemma bit_eqI: \a = b\ if \\n. bit a n \ bit b n\ using that proof (induction a arbitrary: b rule: bits_induct) case (stable a) from stable(2) [of 0] have **: \even b \ even a\ by simp have \b div 2 = b\ proof (rule bit_iff_idd_imp_stable) fix n from stable have *: \bit b n \ bit a n\ by simp also have \bit a n \ odd a\ using stable by (simp add: stable_imp_bit_iff_odd) finally show \bit b n \ odd b\ by (simp add: **) qed from ** have \a mod 2 = b mod 2\ by (simp add: mod2_eq_if) then have \a mod 2 + (a + b) = b mod 2 + (a + b)\ by simp then have \a + a mod 2 + b = b + b mod 2 + a\ by (simp add: ac_simps) with \a div 2 = a\ \b div 2 = b\ show ?case by (simp add: bits_stable_imp_add_self) next case (rec a p) from rec.prems [of 0] have [simp]: \p = odd b\ by simp from rec.hyps have \bit a n \ bit (b div 2) n\ for n using rec.prems [of \Suc n\] by simp then have \a = b div 2\ by (rule rec.IH) then have \2 * a = 2 * (b div 2)\ by simp then have \b mod 2 + 2 * a = b mod 2 + 2 * (b div 2)\ by simp also have \\ = b\ by (fact mod_mult_div_eq) finally show ?case by (auto simp add: mod2_eq_if) qed lemma bit_eq_iff: \a = b \ (\n. bit a n \ bit b n)\ by (auto intro: bit_eqI) lemma bit_eq_rec: \a = b \ (even a \ even b) \ a div 2 = b div 2\ apply (simp add: bit_eq_iff) apply auto using bit_0 apply blast using bit_0 apply blast using bit_Suc apply blast using bit_Suc apply blast apply (metis bit_eq_iff local.even_iff_mod_2_eq_zero local.mod_div_mult_eq) apply (metis bit_eq_iff local.even_iff_mod_2_eq_zero local.mod_div_mult_eq) apply (metis bit_eq_iff local.mod2_eq_if local.mod_div_mult_eq) apply (metis bit_eq_iff local.mod2_eq_if local.mod_div_mult_eq) done lemma bit_exp_iff: \bit (2 ^ m) n \ 2 ^ m \ 0 \ m = n\ by (auto simp add: bit_def exp_div_exp_eq) lemma bit_1_iff: \bit 1 n \ 1 \ 0 \ n = 0\ using bit_exp_iff [of 0 n] by simp lemma bit_2_iff: \bit 2 n \ 2 \ 0 \ n = 1\ using bit_exp_iff [of 1 n] by auto end lemma nat_bit_induct [case_names zero even odd]: "P n" if zero: "P 0" and even: "\n. P n \ n > 0 \ P (2 * n)" and odd: "\n. P n \ P (Suc (2 * n))" proof (induction n rule: less_induct) case (less n) show "P n" proof (cases "n = 0") case True with zero show ?thesis by simp next case False with less have hyp: "P (n div 2)" by simp show ?thesis proof (cases "even n") case True then have "n \ 1" by auto with \n \ 0\ have "n div 2 > 0" by simp with \even n\ hyp even [of "n div 2"] show ?thesis by simp next case False with hyp odd [of "n div 2"] show ?thesis by simp qed qed qed instance nat :: semiring_bits proof show \P n\ if stable: \\n. n div 2 = n \ P n\ and rec: \\n b. P n \ (of_bool b + 2 * n) div 2 = n \ P (of_bool b + 2 * n)\ for P and n :: nat proof (induction n rule: nat_bit_induct) case zero from stable [of 0] show ?case by simp next case (even n) with rec [of n False] show ?case by simp next case (odd n) with rec [of n True] show ?case by simp qed show \q mod 2 ^ m mod 2 ^ n = q mod 2 ^ min m n\ for q m n :: nat apply (auto simp add: less_iff_Suc_add power_add mod_mod_cancel split: split_min_lin) apply (metis div_mult2_eq mod_div_trivial mod_eq_self_iff_div_eq_0 mod_mult_self2_is_0 power_commutes) done show \(q * 2 ^ m) mod (2 ^ n) = (q mod 2 ^ (n - m)) * 2 ^ m\ if \m \ n\ for q m n :: nat using that apply (auto simp add: mod_mod_cancel div_mult2_eq power_add mod_mult2_eq le_iff_add split: split_min_lin) apply (simp add: mult.commute) done qed (auto simp add: div_mult2_eq mod_mult2_eq power_add power_diff) lemma int_bit_induct [case_names zero minus even odd]: "P k" if zero_int: "P 0" and minus_int: "P (- 1)" and even_int: "\k. P k \ k \ 0 \ P (k * 2)" and odd_int: "\k. P k \ k \ - 1 \ P (1 + (k * 2))" for k :: int proof (cases "k \ 0") case True define n where "n = nat k" with True have "k = int n" by simp then show "P k" proof (induction n arbitrary: k rule: nat_bit_induct) case zero then show ?case by (simp add: zero_int) next case (even n) have "P (int n * 2)" by (rule even_int) (use even in simp_all) with even show ?case by (simp add: ac_simps) next case (odd n) have "P (1 + (int n * 2))" by (rule odd_int) (use odd in simp_all) with odd show ?case by (simp add: ac_simps) qed next case False define n where "n = nat (- k - 1)" with False have "k = - int n - 1" by simp then show "P k" proof (induction n arbitrary: k rule: nat_bit_induct) case zero then show ?case by (simp add: minus_int) next case (even n) have "P (1 + (- int (Suc n) * 2))" by (rule odd_int) (use even in \simp_all add: algebra_simps\) also have "\ = - int (2 * n) - 1" by (simp add: algebra_simps) finally show ?case using even by simp next case (odd n) have "P (- int (Suc n) * 2)" by (rule even_int) (use odd in \simp_all add: algebra_simps\) also have "\ = - int (Suc (2 * n)) - 1" by (simp add: algebra_simps) finally show ?case using odd by simp qed qed instance int :: semiring_bits proof show \P k\ if stable: \\k. k div 2 = k \ P k\ and rec: \\k b. P k \ (of_bool b + 2 * k) div 2 = k \ P (of_bool b + 2 * k)\ for P and k :: int proof (induction k rule: int_bit_induct) case zero from stable [of 0] show ?case by simp next case minus from stable [of \- 1\] show ?case by simp next case (even k) with rec [of k False] show ?case by (simp add: ac_simps) next case (odd k) with rec [of k True] show ?case by (simp add: ac_simps) qed show \(2::int) ^ m div 2 ^ n = of_bool ((2::int) ^ m \ 0 \ n \ m) * 2 ^ (m - n)\ for m n :: nat proof (cases \m < n\) case True then have \n = m + (n - m)\ by simp then have \(2::int) ^ m div 2 ^ n = (2::int) ^ m div 2 ^ (m + (n - m))\ by simp also have \\ = (2::int) ^ m div (2 ^ m * 2 ^ (n - m))\ by (simp add: power_add) also have \\ = (2::int) ^ m div 2 ^ m div 2 ^ (n - m)\ by (simp add: zdiv_zmult2_eq) finally show ?thesis using \m < n\ by simp next case False then show ?thesis by (simp add: power_diff) qed show \k mod 2 ^ m mod 2 ^ n = k mod 2 ^ min m n\ for m n :: nat and k :: int using mod_exp_eq [of \nat k\ m n] apply (auto simp add: mod_mod_cancel zdiv_zmult2_eq power_add zmod_zmult2_eq le_iff_add split: split_min_lin) apply (auto simp add: less_iff_Suc_add mod_mod_cancel power_add) apply (simp only: flip: mult.left_commute [of \2 ^ m\]) apply (subst zmod_zmult2_eq) apply simp_all done show \(k * 2 ^ m) mod (2 ^ n) = (k mod 2 ^ (n - m)) * 2 ^ m\ if \m \ n\ for m n :: nat and k :: int using that apply (auto simp add: power_add zmod_zmult2_eq le_iff_add split: split_min_lin) apply (simp add: ac_simps) done qed (auto simp add: zdiv_zmult2_eq zmod_zmult2_eq power_add power_diff not_le) class semiring_bit_shifts = semiring_bits + fixes push_bit :: \nat \ 'a \ 'a\ assumes push_bit_eq_mult: \push_bit n a = a * 2 ^ n\ fixes drop_bit :: \nat \ 'a \ 'a\ assumes drop_bit_eq_div: \drop_bit n a = a div 2 ^ n\ begin definition take_bit :: \nat \ 'a \ 'a\ where take_bit_eq_mod: \take_bit n a = a mod 2 ^ n\ text \ Logically, \<^const>\push_bit\, \<^const>\drop_bit\ and \<^const>\take_bit\ are just aliases; having them as separate operations makes proofs easier, otherwise proof automation would fiddle with concrete expressions \<^term>\2 ^ n\ in a way obfuscating the basic algebraic relationships between those operations. Having \<^const>\push_bit\ and \<^const>\drop_bit\ as definitional class operations takes into account that specific instances of these can be implemented differently wrt. code generation. \ lemma bit_iff_odd_drop_bit: \bit a n \ odd (drop_bit n a)\ by (simp add: bit_def drop_bit_eq_div) lemma even_drop_bit_iff_not_bit: \even (drop_bit n a) \ \ bit a n\ by (simp add: bit_iff_odd_drop_bit) lemma bits_ident: "push_bit n (drop_bit n a) + take_bit n a = a" using div_mult_mod_eq by (simp add: push_bit_eq_mult take_bit_eq_mod drop_bit_eq_div) lemma push_bit_push_bit [simp]: "push_bit m (push_bit n a) = push_bit (m + n) a" by (simp add: push_bit_eq_mult power_add ac_simps) lemma push_bit_0_id [simp]: "push_bit 0 = id" by (simp add: fun_eq_iff push_bit_eq_mult) lemma push_bit_of_0 [simp]: "push_bit n 0 = 0" by (simp add: push_bit_eq_mult) lemma push_bit_of_1: "push_bit n 1 = 2 ^ n" by (simp add: push_bit_eq_mult) lemma push_bit_Suc [simp]: "push_bit (Suc n) a = push_bit n (a * 2)" by (simp add: push_bit_eq_mult ac_simps) lemma push_bit_double: "push_bit n (a * 2) = push_bit n a * 2" by (simp add: push_bit_eq_mult ac_simps) lemma push_bit_add: "push_bit n (a + b) = push_bit n a + push_bit n b" by (simp add: push_bit_eq_mult algebra_simps) lemma take_bit_0 [simp]: "take_bit 0 a = 0" by (simp add: take_bit_eq_mod) lemma take_bit_Suc [simp]: \take_bit (Suc n) a = take_bit n (a div 2) * 2 + of_bool (odd a)\ proof - have \take_bit (Suc n) (a div 2 * 2 + of_bool (odd a)) = take_bit n (a div 2) * 2 + of_bool (odd a)\ using even_succ_mod_exp [of \2 * (a div 2)\ \Suc n\] mult_exp_mod_exp_eq [of 1 \Suc n\ \a div 2\] by (auto simp add: take_bit_eq_mod ac_simps) then show ?thesis using div_mult_mod_eq [of a 2] by (simp add: mod_2_eq_odd) qed lemma take_bit_of_0 [simp]: "take_bit n 0 = 0" by (simp add: take_bit_eq_mod) lemma take_bit_of_1 [simp]: "take_bit n 1 = of_bool (n > 0)" by (cases n) simp_all lemma drop_bit_of_0 [simp]: "drop_bit n 0 = 0" by (simp add: drop_bit_eq_div) lemma drop_bit_of_1 [simp]: "drop_bit n 1 = of_bool (n = 0)" by (simp add: drop_bit_eq_div) lemma drop_bit_0 [simp]: "drop_bit 0 = id" by (simp add: fun_eq_iff drop_bit_eq_div) lemma drop_bit_Suc [simp]: "drop_bit (Suc n) a = drop_bit n (a div 2)" using div_exp_eq [of a 1] by (simp add: drop_bit_eq_div) lemma drop_bit_half: "drop_bit n (a div 2) = drop_bit n a div 2" by (induction n arbitrary: a) simp_all lemma drop_bit_of_bool [simp]: "drop_bit n (of_bool d) = of_bool (n = 0 \ d)" by (cases n) simp_all lemma take_bit_eq_0_imp_dvd: "take_bit n a = 0 \ 2 ^ n dvd a" by (simp add: take_bit_eq_mod mod_0_imp_dvd) lemma even_take_bit_eq [simp]: \even (take_bit n a) \ n = 0 \ even a\ by (cases n) simp_all lemma take_bit_take_bit [simp]: "take_bit m (take_bit n a) = take_bit (min m n) a" by (simp add: take_bit_eq_mod mod_exp_eq ac_simps) lemma drop_bit_drop_bit [simp]: "drop_bit m (drop_bit n a) = drop_bit (m + n) a" by (simp add: drop_bit_eq_div power_add div_exp_eq ac_simps) lemma push_bit_take_bit: "push_bit m (take_bit n a) = take_bit (m + n) (push_bit m a)" apply (simp add: push_bit_eq_mult take_bit_eq_mod power_add ac_simps) using mult_exp_mod_exp_eq [of m \m + n\ a] apply (simp add: ac_simps power_add) done lemma take_bit_push_bit: "take_bit m (push_bit n a) = push_bit n (take_bit (m - n) a)" proof (cases "m \ n") case True then show ?thesis apply (simp add:) apply (simp_all add: push_bit_eq_mult take_bit_eq_mod) apply (auto dest!: le_Suc_ex simp add: power_add ac_simps) using mult_exp_mod_exp_eq [of m m \a * 2 ^ n\ for n] apply (simp add: ac_simps) done next case False then show ?thesis using push_bit_take_bit [of n "m - n" a] by simp qed lemma take_bit_drop_bit: "take_bit m (drop_bit n a) = drop_bit n (take_bit (m + n) a)" by (simp add: drop_bit_eq_div take_bit_eq_mod ac_simps div_exp_mod_exp_eq) lemma drop_bit_take_bit: "drop_bit m (take_bit n a) = take_bit (n - m) (drop_bit m a)" proof (cases "m \ n") case True then show ?thesis using take_bit_drop_bit [of "n - m" m a] by simp next case False then obtain q where \m = n + q\ by (auto simp add: not_le dest: less_imp_Suc_add) then have \drop_bit m (take_bit n a) = 0\ using div_exp_eq [of \a mod 2 ^ n\ n q] by (simp add: take_bit_eq_mod drop_bit_eq_div) with False show ?thesis by simp qed lemma bit_drop_bit_eq: \bit (drop_bit n a) = bit a \ (+) n\ by (simp add: bit_def fun_eq_iff ac_simps flip: drop_bit_eq_div) lemma bit_take_bit_iff: \bit (take_bit m a) n \ n < m \ bit a n\ by (simp add: bit_def drop_bit_take_bit not_le flip: drop_bit_eq_div) end instantiation nat :: semiring_bit_shifts begin definition push_bit_nat :: \nat \ nat \ nat\ where \push_bit_nat n m = m * 2 ^ n\ definition drop_bit_nat :: \nat \ nat \ nat\ where \drop_bit_nat n m = m div 2 ^ n\ instance proof show \push_bit n m = m * 2 ^ n\ for n m :: nat by (simp add: push_bit_nat_def) show \drop_bit n m = m div 2 ^ n\ for n m :: nat by (simp add: drop_bit_nat_def) qed end instantiation int :: semiring_bit_shifts begin definition push_bit_int :: \nat \ int \ int\ where \push_bit_int n k = k * 2 ^ n\ definition drop_bit_int :: \nat \ int \ int\ where \drop_bit_int n k = k div 2 ^ n\ instance proof show \push_bit n k = k * 2 ^ n\ for n :: nat and k :: int by (simp add: push_bit_int_def) show \drop_bit n k = k div 2 ^ n\ for n :: nat and k :: int by (simp add: drop_bit_int_def) qed end +lemma bit_push_bit_iff_nat: + \bit (push_bit m q) n \ m \ n \ bit q (n - m)\ for q :: nat +proof (cases \m \ n\) + case True + then obtain r where \n = m + r\ + using le_Suc_ex by blast + with True show ?thesis + by (simp add: push_bit_eq_mult bit_def power_add mult.commute [of \2 ^ m\]) +next + case False + then obtain r where \m = Suc (n + r)\ + using less_imp_Suc_add not_le by blast + with False show ?thesis + by (simp add: push_bit_eq_mult bit_def power_add mult.left_commute [of _ \2 ^ n\]) +qed + +lemma bit_push_bit_iff_int: + \bit (push_bit m k) n \ m \ n \ bit k (n - m)\ for k :: int +proof (cases \m \ n\) + case True + then obtain r where \n = m + r\ + using le_Suc_ex by blast + with True show ?thesis + by (simp add: push_bit_eq_mult bit_def power_add mult.commute [of \2 ^ m\]) +next + case False + then obtain r where \m = Suc (n + r)\ + using less_imp_Suc_add not_le by blast + with False show ?thesis + by (simp add: push_bit_eq_mult bit_def power_add mult.left_commute [of _ \2 ^ n\]) +qed + class unique_euclidean_semiring_with_bit_shifts = unique_euclidean_semiring_with_nat + semiring_bit_shifts begin lemma take_bit_of_exp [simp]: \take_bit m (2 ^ n) = of_bool (n < m) * 2 ^ n\ by (simp add: take_bit_eq_mod exp_mod_exp) lemma take_bit_of_2 [simp]: \take_bit n 2 = of_bool (2 \ n) * 2\ using take_bit_of_exp [of n 1] by simp -lemma take_bit_of_range: +lemma take_bit_of_mask: \take_bit m (2 ^ n - 1) = 2 ^ min m n - 1\ - by (simp add: take_bit_eq_mod range_mod_exp) + by (simp add: take_bit_eq_mod mask_mod_exp) lemma push_bit_eq_0_iff [simp]: "push_bit n a = 0 \ a = 0" by (simp add: push_bit_eq_mult) lemma push_bit_numeral [simp]: "push_bit (numeral l) (numeral k) = push_bit (pred_numeral l) (numeral (Num.Bit0 k))" by (simp only: numeral_eq_Suc power_Suc numeral_Bit0 [of k] mult_2 [symmetric]) (simp add: ac_simps) lemma push_bit_of_nat: "push_bit n (of_nat m) = of_nat (push_bit n m)" by (simp add: push_bit_eq_mult Parity.push_bit_eq_mult) lemma take_bit_add: "take_bit n (take_bit n a + take_bit n b) = take_bit n (a + b)" by (simp add: take_bit_eq_mod mod_simps) lemma take_bit_eq_0_iff: "take_bit n a = 0 \ 2 ^ n dvd a" by (simp add: take_bit_eq_mod mod_eq_0_iff_dvd) lemma take_bit_of_1_eq_0_iff [simp]: "take_bit n 1 = 0 \ n = 0" by (simp add: take_bit_eq_mod) lemma take_bit_numeral_bit0 [simp]: "take_bit (numeral l) (numeral (Num.Bit0 k)) = take_bit (pred_numeral l) (numeral k) * 2" by (simp only: numeral_eq_Suc power_Suc numeral_Bit0 [of k] mult_2 [symmetric] take_bit_Suc ac_simps even_mult_iff nonzero_mult_div_cancel_right [OF numeral_neq_zero]) simp lemma take_bit_numeral_bit1 [simp]: "take_bit (numeral l) (numeral (Num.Bit1 k)) = take_bit (pred_numeral l) (numeral k) * 2 + 1" by (simp only: numeral_eq_Suc power_Suc numeral_Bit1 [of k] mult_2 [symmetric] take_bit_Suc ac_simps even_add even_mult_iff div_mult_self1 [OF numeral_neq_zero]) (simp add: ac_simps) lemma take_bit_of_nat: "take_bit n (of_nat m) = of_nat (take_bit n m)" by (simp add: take_bit_eq_mod Parity.take_bit_eq_mod of_nat_mod [of m "2 ^ n"]) lemma drop_bit_numeral_bit0 [simp]: "drop_bit (numeral l) (numeral (Num.Bit0 k)) = drop_bit (pred_numeral l) (numeral k)" by (simp only: numeral_eq_Suc power_Suc numeral_Bit0 [of k] mult_2 [symmetric] drop_bit_Suc nonzero_mult_div_cancel_left [OF numeral_neq_zero]) lemma drop_bit_numeral_bit1 [simp]: "drop_bit (numeral l) (numeral (Num.Bit1 k)) = drop_bit (pred_numeral l) (numeral k)" by (simp only: numeral_eq_Suc power_Suc numeral_Bit1 [of k] mult_2 [symmetric] drop_bit_Suc div_mult_self4 [OF numeral_neq_zero]) simp lemma drop_bit_of_nat: "drop_bit n (of_nat m) = of_nat (drop_bit n m)" by (simp add: drop_bit_eq_div Parity.drop_bit_eq_div of_nat_div [of m "2 ^ n"]) +lemma bit_of_nat_iff_bit [simp]: + \bit (of_nat m) n \ bit m n\ +proof - + have \even (m div 2 ^ n) \ even (of_nat (m div 2 ^ n))\ + by simp + also have \of_nat (m div 2 ^ n) = of_nat m div of_nat (2 ^ n)\ + by (simp add: of_nat_div) + finally show ?thesis + by (simp add: bit_def semiring_bits_class.bit_def) +qed + +lemma of_nat_push_bit: + \of_nat (push_bit m n) = push_bit m (of_nat n)\ + by (simp add: push_bit_eq_mult semiring_bit_shifts_class.push_bit_eq_mult) + +lemma of_nat_drop_bit: + \of_nat (drop_bit m n) = drop_bit m (of_nat n)\ + by (simp add: drop_bit_eq_div semiring_bit_shifts_class.drop_bit_eq_div of_nat_div) + +lemma of_nat_take_bit: + \of_nat (take_bit m n) = take_bit m (of_nat n)\ + by (simp add: take_bit_eq_mod semiring_bit_shifts_class.take_bit_eq_mod of_nat_mod) + +lemma bit_push_bit_iff_of_nat_iff: + \bit (push_bit m (of_nat r)) n \ m \ n \ bit (of_nat r) (n - m)\ +proof - + from bit_push_bit_iff_nat + have \bit (of_nat (push_bit m r)) n \ m \ n \ bit (of_nat r) (n - m)\ + by simp + then show ?thesis + by (simp add: of_nat_push_bit) +qed + end instance nat :: unique_euclidean_semiring_with_bit_shifts .. instance int :: unique_euclidean_semiring_with_bit_shifts .. lemma push_bit_of_Suc_0 [simp]: "push_bit n (Suc 0) = 2 ^ n" using push_bit_of_1 [where ?'a = nat] by simp lemma take_bit_of_Suc_0 [simp]: "take_bit n (Suc 0) = of_bool (0 < n)" using take_bit_of_1 [where ?'a = nat] by simp lemma drop_bit_of_Suc_0 [simp]: "drop_bit n (Suc 0) = of_bool (n = 0)" using drop_bit_of_1 [where ?'a = nat] by simp lemma take_bit_eq_self: \take_bit n m = m\ if \m < 2 ^ n\ for n m :: nat using that by (simp add: take_bit_eq_mod) lemma push_bit_minus_one: "push_bit n (- 1 :: int) = - (2 ^ n)" by (simp add: push_bit_eq_mult) lemma minus_1_div_exp_eq_int: \- 1 div (2 :: int) ^ n = - 1\ by (induction n) (use div_exp_eq [symmetric, of \- 1 :: int\ 1] in \simp_all add: ac_simps\) lemma drop_bit_minus_one [simp]: \drop_bit n (- 1 :: int) = - 1\ by (simp add: drop_bit_eq_div minus_1_div_exp_eq_int) lemma take_bit_uminus: "take_bit n (- (take_bit n k)) = take_bit n (- k)" for k :: int by (simp add: take_bit_eq_mod mod_minus_eq) lemma take_bit_minus: "take_bit n (take_bit n k - take_bit n l) = take_bit n (k - l)" for k l :: int by (simp add: take_bit_eq_mod mod_diff_eq) lemma take_bit_nonnegative [simp]: "take_bit n k \ 0" for k :: int by (simp add: take_bit_eq_mod) end diff --git a/src/HOL/ex/Bit_Operations.thy b/src/HOL/ex/Bit_Operations.thy --- a/src/HOL/ex/Bit_Operations.thy +++ b/src/HOL/ex/Bit_Operations.thy @@ -1,847 +1,775 @@ (* Author: Florian Haftmann, TUM *) section \Proof of concept for purely algebraically founded lists of bits\ theory Bit_Operations imports "HOL-Library.Boolean_Algebra" Main begin -lemma bit_push_bit_eq_int: - \bit (push_bit m k) n \ m \ n \ bit k (n - m)\ for k :: int -proof (cases \m \ n\) - case True - then obtain q where \n = m + q\ - using le_Suc_ex by blast - with True show ?thesis - by (simp add: push_bit_eq_mult bit_def power_add) -next - case False - then obtain q where \m = Suc (n + q)\ - using less_imp_Suc_add not_le by blast - with False show ?thesis - by (simp add: push_bit_eq_mult bit_def power_add) -qed - context semiring_bits begin -(*lemma range_rec: - \2 ^ Suc n - 1 = 1 + 2 * (2 ^ n - 1)\ +(*lemma even_mask_div_iff: + \even ((2 ^ m - 1) div 2 ^ n) \ 2 ^ n = 0 \ m \ n\ sorry -lemma even_range_div_iff: - \even ((2 ^ m - 1) div 2 ^ n) \ 2 ^ n = 0 \ m \ n\ - sorry*) - -(*lemma even_range_iff [simp]: - \even (2 ^ n - 1) \ n = 0\ - by (induction n) (simp_all only: range_rec, simp_all) - -lemma bit_range_iff: +lemma bit_mask_iff: \bit (2 ^ m - 1) n \ 2 ^ n \ 0 \ n < m\ - by (simp add: bit_def even_range_div_iff not_le)*) + by (simp add: bit_def even_mask_div_iff not_le)*) end context semiring_bit_shifts begin (*lemma bit_push_bit_iff: \bit (push_bit m a) n \ n \ m \ 2 ^ n \ 0 \ bit a (n - m)\*) end subsection \Bit operations in suitable algebraic structures\ class semiring_bit_operations = semiring_bit_shifts + fixes "and" :: \'a \ 'a \ 'a\ (infixr "AND" 64) and or :: \'a \ 'a \ 'a\ (infixr "OR" 59) and xor :: \'a \ 'a \ 'a\ (infixr "XOR" 59) assumes bit_and_iff: \\n. bit (a AND b) n \ bit a n \ bit b n\ and bit_or_iff: \\n. bit (a OR b) n \ bit a n \ bit b n\ and bit_xor_iff: \\n. bit (a XOR b) n \ bit a n \ bit b n\ begin text \ We want the bitwise operations to bind slightly weaker than \+\ and \-\. For the sake of code generation the operations \<^const>\and\, \<^const>\or\ and \<^const>\xor\ are specified as definitional class operations. \ definition map_bit :: \nat \ (bool \ bool) \ 'a \ 'a\ where \map_bit n f a = take_bit n a + push_bit n (of_bool (f (bit a n)) + 2 * drop_bit (Suc n) a)\ definition set_bit :: \nat \ 'a \ 'a\ where \set_bit n = map_bit n top\ definition unset_bit :: \nat \ 'a \ 'a\ where \unset_bit n = map_bit n bot\ definition flip_bit :: \nat \ 'a \ 'a\ where \flip_bit n = map_bit n Not\ text \ Having \<^const>\set_bit\, \<^const>\unset_bit\ and \<^const>\flip_bit\ as separate operations allows to implement them using bit masks later. \ lemma stable_imp_drop_eq: \drop_bit n a = a\ if \a div 2 = a\ by (induction n) (simp_all add: that) lemma map_bit_0 [simp]: \map_bit 0 f a = of_bool (f (odd a)) + 2 * (a div 2)\ by (simp add: map_bit_def) lemma map_bit_Suc [simp]: \map_bit (Suc n) f a = a mod 2 + 2 * map_bit n f (a div 2)\ by (auto simp add: map_bit_def algebra_simps mod2_eq_if push_bit_add mult_2 elim: evenE oddE) lemma set_bit_0 [simp]: \set_bit 0 a = 1 + 2 * (a div 2)\ by (simp add: set_bit_def) lemma set_bit_Suc [simp]: \set_bit (Suc n) a = a mod 2 + 2 * set_bit n (a div 2)\ by (simp add: set_bit_def) lemma unset_bit_0 [simp]: \unset_bit 0 a = 2 * (a div 2)\ by (simp add: unset_bit_def) lemma unset_bit_Suc [simp]: \unset_bit (Suc n) a = a mod 2 + 2 * unset_bit n (a div 2)\ by (simp add: unset_bit_def) lemma flip_bit_0 [simp]: \flip_bit 0 a = of_bool (even a) + 2 * (a div 2)\ by (simp add: flip_bit_def) lemma flip_bit_Suc [simp]: \flip_bit (Suc n) a = a mod 2 + 2 * flip_bit n (a div 2)\ by (simp add: flip_bit_def) +lemma zero_and_eq [simp]: + "0 AND a = 0" + by (simp add: bit_eq_iff bit_and_iff) + +lemma and_zero_eq [simp]: + "a AND 0 = 0" + by (simp add: bit_eq_iff bit_and_iff) + +lemma zero_or_eq [simp]: + "0 OR a = a" + by (simp add: bit_eq_iff bit_or_iff) + +lemma or_zero_eq [simp]: + "a OR 0 = a" + by (simp add: bit_eq_iff bit_or_iff) + +lemma zero_xor_eq [simp]: + "0 XOR a = a" + by (simp add: bit_eq_iff bit_xor_iff) + +lemma xor_zero_eq [simp]: + "a XOR 0 = a" + by (simp add: bit_eq_iff bit_xor_iff) + lemma take_bit_and [simp]: \take_bit n (a AND b) = take_bit n a AND take_bit n b\ by (auto simp add: bit_eq_iff bit_take_bit_iff bit_and_iff) lemma take_bit_or [simp]: \take_bit n (a OR b) = take_bit n a OR take_bit n b\ by (auto simp add: bit_eq_iff bit_take_bit_iff bit_or_iff) lemma take_bit_xor [simp]: \take_bit n (a XOR b) = take_bit n a XOR take_bit n b\ by (auto simp add: bit_eq_iff bit_take_bit_iff bit_xor_iff) end class ring_bit_operations = semiring_bit_operations + ring_parity + fixes not :: \'a \ 'a\ (\NOT\) assumes bit_not_iff: \\n. bit (NOT a) n \ 2 ^ n \ 0 \ \ bit a n\ assumes minus_eq_not_minus_1: \- a = NOT (a - 1)\ begin text \ For the sake of code generation \<^const>\not\ is specified as definitional class operation. Note that \<^const>\not\ has no sensible definition for unlimited but only positive bit strings (type \<^typ>\nat\). \ lemma bits_minus_1_mod_2_eq [simp]: \(- 1) mod 2 = 1\ by (simp add: mod_2_eq_odd) lemma not_eq_complement: \NOT a = - a - 1\ using minus_eq_not_minus_1 [of \a + 1\] by simp lemma minus_eq_not_plus_1: \- a = NOT a + 1\ using not_eq_complement [of a] by simp lemma bit_minus_iff: \bit (- a) n \ 2 ^ n \ 0 \ \ bit (a - 1) n\ by (simp add: minus_eq_not_minus_1 bit_not_iff) lemma bit_not_exp_iff: \bit (NOT (2 ^ m)) n \ 2 ^ n \ 0 \ n \ m\ by (auto simp add: bit_not_iff bit_exp_iff) lemma bit_minus_1_iff [simp]: \bit (- 1) n \ 2 ^ n \ 0\ by (simp add: bit_minus_iff) lemma bit_minus_exp_iff: \bit (- (2 ^ m)) n \ 2 ^ n \ 0 \ n \ m\ oops lemma bit_minus_2_iff [simp]: \bit (- 2) n \ 2 ^ n \ 0 \ n > 0\ by (simp add: bit_minus_iff bit_1_iff) sublocale bit: boolean_algebra \(AND)\ \(OR)\ NOT 0 \- 1\ rewrites \bit.xor = (XOR)\ proof - interpret bit: boolean_algebra \(AND)\ \(OR)\ NOT 0 \- 1\ apply standard apply (auto simp add: bit_eq_iff bit_and_iff bit_or_iff bit_not_iff) apply (simp_all add: bit_exp_iff) apply (metis local.bit_def local.bit_exp_iff local.bits_div_by_0) apply (metis local.bit_def local.bit_exp_iff local.bits_div_by_0) done show \boolean_algebra (AND) (OR) NOT 0 (- 1)\ by standard show \boolean_algebra.xor (AND) (OR) NOT = (XOR)\ apply (auto simp add: fun_eq_iff bit.xor_def bit_eq_iff bit_and_iff bit_or_iff bit_not_iff bit_xor_iff) apply (simp add: bit_exp_iff, simp add: bit_def) apply (metis local.bit_def local.bit_exp_iff local.bits_div_by_0) apply (metis local.bit_def local.bit_exp_iff local.bits_div_by_0) apply (simp_all add: bit_exp_iff, simp_all add: bit_def) done qed +lemma push_bit_minus: + \push_bit n (- a) = - push_bit n a\ + by (simp add: push_bit_eq_mult) + lemma take_bit_not_take_bit: \take_bit n (NOT (take_bit n a)) = take_bit n (NOT a)\ by (auto simp add: bit_eq_iff bit_take_bit_iff bit_not_iff) end subsubsection \Instance \<^typ>\nat\\ locale zip_nat = single: abel_semigroup f for f :: "bool \ bool \ bool" (infixl "\<^bold>*" 70) + assumes end_of_bits: "\ False \<^bold>* False" begin lemma False_P_imp: "False \<^bold>* True \ P" if "False \<^bold>* P" using that end_of_bits by (cases P) simp_all function F :: "nat \ nat \ nat" (infixl "\<^bold>\" 70) where "m \<^bold>\ n = (if m = 0 \ n = 0 then 0 else of_bool (odd m \<^bold>* odd n) + (m div 2) \<^bold>\ (n div 2) * 2)" by auto termination by (relation "measure (case_prod (+))") auto lemma zero_left_eq: "0 \<^bold>\ n = of_bool (False \<^bold>* True) * n" by (induction n rule: nat_bit_induct) (simp_all add: end_of_bits) lemma zero_right_eq: "m \<^bold>\ 0 = of_bool (True \<^bold>* False) * m" by (induction m rule: nat_bit_induct) (simp_all add: end_of_bits) lemma simps [simp]: "0 \<^bold>\ 0 = 0" "0 \<^bold>\ n = of_bool (False \<^bold>* True) * n" "m \<^bold>\ 0 = of_bool (True \<^bold>* False) * m" "m > 0 \ n > 0 \ m \<^bold>\ n = of_bool (odd m \<^bold>* odd n) + (m div 2) \<^bold>\ (n div 2) * 2" by (simp_all only: zero_left_eq zero_right_eq) simp lemma rec: "m \<^bold>\ n = of_bool (odd m \<^bold>* odd n) + (m div 2) \<^bold>\ (n div 2) * 2" by (cases "m = 0 \ n = 0") (auto simp add: end_of_bits) declare F.simps [simp del] sublocale abel_semigroup F proof show "m \<^bold>\ n \<^bold>\ q = m \<^bold>\ (n \<^bold>\ q)" for m n q :: nat proof (induction m arbitrary: n q rule: nat_bit_induct) case zero show ?case by simp next case (even m) with rec [of "2 * m"] rec [of _ q] show ?case by (cases "even n") (auto simp add: ac_simps dest: False_P_imp) next case (odd m) with rec [of "Suc (2 * m)"] rec [of _ q] show ?case by (cases "even n"; cases "even q") (auto dest: False_P_imp simp add: ac_simps) qed show "m \<^bold>\ n = n \<^bold>\ m" for m n :: nat proof (induction m arbitrary: n rule: nat_bit_induct) case zero show ?case by (simp add: ac_simps) next case (even m) with rec [of "2 * m" n] rec [of n "2 * m"] show ?case by (simp add: ac_simps) next case (odd m) with rec [of "Suc (2 * m)" n] rec [of n "Suc (2 * m)"] show ?case by (simp add: ac_simps) qed qed lemma self [simp]: "n \<^bold>\ n = of_bool (True \<^bold>* True) * n" by (induction n rule: nat_bit_induct) (simp_all add: end_of_bits) lemma even_iff [simp]: "even (m \<^bold>\ n) \ \ (odd m \<^bold>* odd n)" proof (induction m arbitrary: n rule: nat_bit_induct) case zero show ?case by (cases "even n") (simp_all add: end_of_bits) next case (even m) then show ?case by (simp add: rec [of "2 * m"]) next case (odd m) then show ?case by (simp add: rec [of "Suc (2 * m)"]) qed end instantiation nat :: semiring_bit_operations begin global_interpretation and_nat: zip_nat "(\)" defines and_nat = and_nat.F by standard auto global_interpretation and_nat: semilattice "(AND) :: nat \ nat \ nat" proof (rule semilattice.intro, fact and_nat.abel_semigroup_axioms, standard) show "n AND n = n" for n :: nat by (simp add: and_nat.self) qed declare and_nat.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ -lemma zero_nat_and_eq [simp]: - "0 AND n = 0" for n :: nat - by simp - -lemma and_zero_nat_eq [simp]: - "n AND 0 = 0" for n :: nat - by simp - global_interpretation or_nat: zip_nat "(\)" defines or_nat = or_nat.F by standard auto global_interpretation or_nat: semilattice "(OR) :: nat \ nat \ nat" proof (rule semilattice.intro, fact or_nat.abel_semigroup_axioms, standard) show "n OR n = n" for n :: nat by (simp add: or_nat.self) qed declare or_nat.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ -lemma zero_nat_or_eq [simp]: - "0 OR n = n" for n :: nat - by simp - -lemma or_zero_nat_eq [simp]: - "n OR 0 = n" for n :: nat - by simp - global_interpretation xor_nat: zip_nat "(\)" defines xor_nat = xor_nat.F by standard auto declare xor_nat.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ -lemma zero_nat_xor_eq [simp]: - "0 XOR n = n" for n :: nat - by simp - -lemma xor_zero_nat_eq [simp]: - "n XOR 0 = n" for n :: nat - by simp - instance proof fix m n q :: nat show \bit (m AND n) q \ bit m q \ bit n q\ proof (rule sym, induction q arbitrary: m n) case 0 then show ?case by (simp add: and_nat.even_iff) next case (Suc q) with and_nat.rec [of m n] show ?case by simp qed show \bit (m OR n) q \ bit m q \ bit n q\ proof (rule sym, induction q arbitrary: m n) case 0 then show ?case by (simp add: or_nat.even_iff) next case (Suc q) with or_nat.rec [of m n] show ?case by simp qed show \bit (m XOR n) q \ bit m q \ bit n q\ proof (rule sym, induction q arbitrary: m n) case 0 then show ?case by (simp add: xor_nat.even_iff) next case (Suc q) with xor_nat.rec [of m n] show ?case by simp qed qed end global_interpretation or_nat: semilattice_neutr "(OR)" "0 :: nat" by standard simp global_interpretation xor_nat: comm_monoid "(XOR)" "0 :: nat" by standard simp lemma Suc_0_and_eq [simp]: "Suc 0 AND n = n mod 2" by (cases n) auto lemma and_Suc_0_eq [simp]: "n AND Suc 0 = n mod 2" using Suc_0_and_eq [of n] by (simp add: ac_simps) lemma Suc_0_or_eq [simp]: "Suc 0 OR n = n + of_bool (even n)" by (cases n) (simp_all add: ac_simps) lemma or_Suc_0_eq [simp]: "n OR Suc 0 = n + of_bool (even n)" using Suc_0_or_eq [of n] by (simp add: ac_simps) lemma Suc_0_xor_eq [simp]: "Suc 0 XOR n = n + of_bool (even n) - of_bool (odd n)" by (cases n) (simp_all add: ac_simps) lemma xor_Suc_0_eq [simp]: "n XOR Suc 0 = n + of_bool (even n) - of_bool (odd n)" using Suc_0_xor_eq [of n] by (simp add: ac_simps) subsubsection \Instance \<^typ>\int\\ abbreviation (input) complement :: "int \ int" where "complement k \ - k - 1" lemma complement_half: "complement (k * 2) div 2 = complement k" by simp lemma complement_div_2: "complement (k div 2) = complement k div 2" by linarith locale zip_int = single: abel_semigroup f for f :: "bool \ bool \ bool" (infixl "\<^bold>*" 70) begin lemma False_False_imp_True_True: "True \<^bold>* True" if "False \<^bold>* False" proof (rule ccontr) assume "\ True \<^bold>* True" with that show False using single.assoc [of False True True] by (cases "False \<^bold>* True") simp_all qed function F :: "int \ int \ int" (infixl "\<^bold>\" 70) where "k \<^bold>\ l = (if k \ {0, - 1} \ l \ {0, - 1} then - of_bool (odd k \<^bold>* odd l) else of_bool (odd k \<^bold>* odd l) + (k div 2) \<^bold>\ (l div 2) * 2)" by auto termination by (relation "measure (\(k, l). nat (\k\ + \l\))") auto lemma zero_left_eq: "0 \<^bold>\ l = (case (False \<^bold>* False, False \<^bold>* True) of (False, False) \ 0 | (False, True) \ l | (True, False) \ complement l | (True, True) \ - 1)" by (induction l rule: int_bit_induct) (simp_all split: bool.split) lemma minus_left_eq: "- 1 \<^bold>\ l = (case (True \<^bold>* False, True \<^bold>* True) of (False, False) \ 0 | (False, True) \ l | (True, False) \ complement l | (True, True) \ - 1)" by (induction l rule: int_bit_induct) (simp_all split: bool.split) lemma zero_right_eq: "k \<^bold>\ 0 = (case (False \<^bold>* False, False \<^bold>* True) of (False, False) \ 0 | (False, True) \ k | (True, False) \ complement k | (True, True) \ - 1)" by (induction k rule: int_bit_induct) (simp_all add: ac_simps split: bool.split) lemma minus_right_eq: "k \<^bold>\ - 1 = (case (True \<^bold>* False, True \<^bold>* True) of (False, False) \ 0 | (False, True) \ k | (True, False) \ complement k | (True, True) \ - 1)" by (induction k rule: int_bit_induct) (simp_all add: ac_simps split: bool.split) lemma simps [simp]: "0 \<^bold>\ 0 = - of_bool (False \<^bold>* False)" "- 1 \<^bold>\ 0 = - of_bool (True \<^bold>* False)" "0 \<^bold>\ - 1 = - of_bool (False \<^bold>* True)" "- 1 \<^bold>\ - 1 = - of_bool (True \<^bold>* True)" "0 \<^bold>\ l = (case (False \<^bold>* False, False \<^bold>* True) of (False, False) \ 0 | (False, True) \ l | (True, False) \ complement l | (True, True) \ - 1)" "- 1 \<^bold>\ l = (case (True \<^bold>* False, True \<^bold>* True) of (False, False) \ 0 | (False, True) \ l | (True, False) \ complement l | (True, True) \ - 1)" "k \<^bold>\ 0 = (case (False \<^bold>* False, False \<^bold>* True) of (False, False) \ 0 | (False, True) \ k | (True, False) \ complement k | (True, True) \ - 1)" "k \<^bold>\ - 1 = (case (True \<^bold>* False, True \<^bold>* True) of (False, False) \ 0 | (False, True) \ k | (True, False) \ complement k | (True, True) \ - 1)" "k \ 0 \ k \ - 1 \ l \ 0 \ l \ - 1 \ k \<^bold>\ l = of_bool (odd k \<^bold>* odd l) + (k div 2) \<^bold>\ (l div 2) * 2" by simp_all[4] (simp_all only: zero_left_eq minus_left_eq zero_right_eq minus_right_eq, simp) declare F.simps [simp del] lemma rec: "k \<^bold>\ l = of_bool (odd k \<^bold>* odd l) + (k div 2) \<^bold>\ (l div 2) * 2" by (cases "k \ {0, - 1} \ l \ {0, - 1}") (auto simp add: ac_simps F.simps [of k l] split: bool.split) sublocale abel_semigroup F proof show "k \<^bold>\ l \<^bold>\ r = k \<^bold>\ (l \<^bold>\ r)" for k l r :: int proof (induction k arbitrary: l r rule: int_bit_induct) case zero have "complement l \<^bold>\ r = complement (l \<^bold>\ r)" if "False \<^bold>* False" "\ False \<^bold>* True" proof (induction l arbitrary: r rule: int_bit_induct) case zero from that show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case minus from that show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case (even l) with that rec [of _ r] show ?case by (cases "even r") (auto simp add: complement_half ac_simps False_False_imp_True_True split: bool.splits) next case (odd l) moreover have "- l - 1 = - 1 - l" by simp ultimately show ?case using that rec [of _ r] by (cases "even r") (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) qed then show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case minus have "complement l \<^bold>\ r = complement (l \<^bold>\ r)" if "\ True \<^bold>* True" "False \<^bold>* True" proof (induction l arbitrary: r rule: int_bit_induct) case zero from that show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case minus from that show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case (even l) with that rec [of _ r] show ?case by (cases "even r") (auto simp add: complement_half ac_simps False_False_imp_True_True split: bool.splits) next case (odd l) moreover have "- l - 1 = - 1 - l" by simp ultimately show ?case using that rec [of _ r] by (cases "even r") (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) qed then show ?case by (auto simp add: ac_simps False_False_imp_True_True split: bool.splits) next case (even k) with rec [of "k * 2"] rec [of _ r] show ?case by (cases "even r"; cases "even l") (auto simp add: ac_simps False_False_imp_True_True) next case (odd k) with rec [of "1 + k * 2"] rec [of _ r] show ?case by (cases "even r"; cases "even l") (auto simp add: ac_simps False_False_imp_True_True) qed show "k \<^bold>\ l = l \<^bold>\ k" for k l :: int proof (induction k arbitrary: l rule: int_bit_induct) case zero show ?case by simp next case minus show ?case by simp next case (even k) with rec [of "k * 2" l] rec [of l "k * 2"] show ?case by (simp add: ac_simps) next case (odd k) with rec [of "k * 2 + 1" l] rec [of l "k * 2 + 1"] show ?case by (simp add: ac_simps) qed qed lemma self [simp]: "k \<^bold>\ k = (case (False \<^bold>* False, True \<^bold>* True) of (False, False) \ 0 | (False, True) \ k | (True, True) \ - 1)" by (induction k rule: int_bit_induct) (auto simp add: False_False_imp_True_True split: bool.split) lemma even_iff [simp]: "even (k \<^bold>\ l) \ \ (odd k \<^bold>* odd l)" proof (induction k arbitrary: l rule: int_bit_induct) case zero show ?case by (cases "even l") (simp_all split: bool.splits) next case minus show ?case by (cases "even l") (simp_all split: bool.splits) next case (even k) then show ?case by (simp add: rec [of "k * 2"]) next case (odd k) then show ?case by (simp add: rec [of "1 + k * 2"]) qed end instantiation int :: ring_bit_operations begin definition not_int :: "int \ int" where "not_int = complement" global_interpretation and_int: zip_int "(\)" defines and_int = and_int.F by standard declare and_int.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ global_interpretation and_int: semilattice "(AND) :: int \ int \ int" proof (rule semilattice.intro, fact and_int.abel_semigroup_axioms, standard) show "k AND k = k" for k :: int by (simp add: and_int.self) qed -lemma zero_int_and_eq [simp]: - "0 AND k = 0" for k :: int - by simp - -lemma and_zero_int_eq [simp]: - "k AND 0 = 0" for k :: int - by simp - -lemma minus_int_and_eq [simp]: - "- 1 AND k = k" for k :: int - by simp - -lemma and_minus_int_eq [simp]: - "k AND - 1 = k" for k :: int - by simp - global_interpretation or_int: zip_int "(\)" defines or_int = or_int.F by standard declare or_int.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ global_interpretation or_int: semilattice "(OR) :: int \ int \ int" proof (rule semilattice.intro, fact or_int.abel_semigroup_axioms, standard) show "k OR k = k" for k :: int by (simp add: or_int.self) qed -lemma zero_int_or_eq [simp]: - "0 OR k = k" for k :: int - by simp - -lemma and_zero_or_eq [simp]: - "k OR 0 = k" for k :: int - by simp - -lemma minus_int_or_eq [simp]: - "- 1 OR k = - 1" for k :: int - by simp - -lemma or_minus_int_eq [simp]: - "k OR - 1 = - 1" for k :: int - by simp - global_interpretation xor_int: zip_int "(\)" defines xor_int = xor_int.F by standard declare xor_int.simps [simp] \ \inconsistent declaration handling by \global_interpretation\ in \instantiation\\ -lemma zero_int_xor_eq [simp]: - "0 XOR k = k" for k :: int - by simp - -lemma and_zero_xor_eq [simp]: - "k XOR 0 = k" for k :: int - by simp - -lemma minus_int_xor_eq [simp]: - "- 1 XOR k = complement k" for k :: int - by simp - -lemma xor_minus_int_eq [simp]: - "k XOR - 1 = complement k" for k :: int - by simp - -lemma not_div_2: - "NOT k div 2 = NOT (k div 2)" - for k :: int - by (simp add: complement_div_2 not_int_def) - -lemma not_int_simps [simp]: - "NOT 0 = (- 1 :: int)" - "NOT (- 1) = (0 :: int)" - "k \ 0 \ k \ - 1 \ NOT k = of_bool (even k) + 2 * NOT (k div 2)" for k :: int - by (auto simp add: not_int_def elim: oddE) - -lemma not_one_int [simp]: - "NOT 1 = (- 2 :: int)" - by simp - -lemma even_not_iff [simp]: - "even (NOT k) \ odd k" - for k :: int - by (simp add: not_int_def) - lemma bit_not_iff_int: \bit (NOT k) n \ \ bit k n\ for k :: int by (induction n arbitrary: k) (simp_all add: not_int_def flip: complement_div_2) instance proof fix k l :: int and n :: nat show \- k = NOT (k - 1)\ by (simp add: not_int_def) show \bit (k AND l) n \ bit k n \ bit l n\ proof (rule sym, induction n arbitrary: k l) case 0 then show ?case by (simp add: and_int.even_iff) next case (Suc n) with and_int.rec [of k l] show ?case by simp qed show \bit (k OR l) n \ bit k n \ bit l n\ proof (rule sym, induction n arbitrary: k l) case 0 then show ?case by (simp add: or_int.even_iff) next case (Suc n) with or_int.rec [of k l] show ?case by simp qed show \bit (k XOR l) n \ bit k n \ bit l n\ proof (rule sym, induction n arbitrary: k l) case 0 then show ?case by (simp add: xor_int.even_iff) next case (Suc n) with xor_int.rec [of k l] show ?case by simp qed qed (simp_all add: minus_1_div_exp_eq_int bit_not_iff_int) end +lemma not_div_2: + "NOT k div 2 = NOT (k div 2)" for k :: int + by (simp add: complement_div_2 not_int_def) + +lemma not_int_rec [simp]: + "k \ 0 \ k \ - 1 \ NOT k = of_bool (even k) + 2 * NOT (k div 2)" for k :: int + by (auto simp add: not_int_def elim: oddE) + +lemma not_one_int [simp]: + "NOT 1 = (- 2 :: int)" + by (simp add: bit_eq_iff bit_not_iff) (simp add: bit_1_iff) + +lemma even_not_int_iff [simp]: + "even (NOT k) \ odd k" for k :: int + using bit_not_iff [of k 0] by auto + lemma one_and_int_eq [simp]: - "1 AND k = k mod 2" for k :: int - by (simp add: bit_eq_iff bit_and_iff mod2_eq_if) (auto simp add: bit_1_iff) + "1 AND k = of_bool (odd k)" for k :: int + by (simp add: bit_eq_iff bit_and_iff) (auto simp add: bit_1_iff) lemma and_one_int_eq [simp]: - "k AND 1 = k mod 2" for k :: int + "k AND 1 = of_bool (odd k)" for k :: int using one_and_int_eq [of 1] by (simp add: ac_simps) lemma one_or_int_eq [simp]: "1 OR k = k + of_bool (even k)" for k :: int using or_int.rec [of 1] by (auto elim: oddE) lemma or_one_int_eq [simp]: "k OR 1 = k + of_bool (even k)" for k :: int using one_or_int_eq [of k] by (simp add: ac_simps) lemma one_xor_int_eq [simp]: "1 XOR k = k + of_bool (even k) - of_bool (odd k)" for k :: int using xor_int.rec [of 1] by (auto elim: oddE) lemma xor_one_int_eq [simp]: "k XOR 1 = k + of_bool (even k) - of_bool (odd k)" for k :: int using one_xor_int_eq [of k] by (simp add: ac_simps) lemma take_bit_complement_iff: "take_bit n (complement k) = take_bit n (complement l) \ take_bit n k = take_bit n l" for k l :: int by (simp add: take_bit_eq_mod mod_eq_dvd_iff dvd_diff_commute) lemma take_bit_not_iff_int: "take_bit n (NOT k) = take_bit n (NOT l) \ take_bit n k = take_bit n l" for k l :: int by (auto simp add: bit_eq_iff bit_take_bit_iff bit_not_iff_int) end diff --git a/src/HOL/ex/Word.thy b/src/HOL/ex/Word.thy --- a/src/HOL/ex/Word.thy +++ b/src/HOL/ex/Word.thy @@ -1,708 +1,708 @@ (* Author: Florian Haftmann, TUM *) section \Proof of concept for algebraically founded bit word types\ theory Word imports Main "HOL-Library.Type_Length" "HOL-ex.Bit_Operations" begin subsection \Preliminaries\ definition signed_take_bit :: "nat \ int \ int" where signed_take_bit_eq_take_bit: "signed_take_bit n k = take_bit (Suc n) (k + 2 ^ n) - 2 ^ n" lemma signed_take_bit_eq_take_bit': "signed_take_bit (n - Suc 0) k = take_bit n (k + 2 ^ (n - 1)) - 2 ^ (n - 1)" if "n > 0" using that by (simp add: signed_take_bit_eq_take_bit) lemma signed_take_bit_0 [simp]: "signed_take_bit 0 k = - (k mod 2)" proof (cases "even k") case True then have "odd (k + 1)" by simp then have "(k + 1) mod 2 = 1" by (simp add: even_iff_mod_2_eq_zero) with True show ?thesis by (simp add: signed_take_bit_eq_take_bit) next case False then show ?thesis by (simp add: signed_take_bit_eq_take_bit odd_iff_mod_2_eq_one) qed lemma signed_take_bit_Suc [simp]: "signed_take_bit (Suc n) k = signed_take_bit n (k div 2) * 2 + k mod 2" by (simp add: odd_iff_mod_2_eq_one signed_take_bit_eq_take_bit algebra_simps) lemma signed_take_bit_of_0 [simp]: "signed_take_bit n 0 = 0" by (simp add: signed_take_bit_eq_take_bit take_bit_eq_mod) lemma signed_take_bit_of_minus_1 [simp]: "signed_take_bit n (- 1) = - 1" by (induct n) simp_all lemma signed_take_bit_eq_iff_take_bit_eq: "signed_take_bit (n - Suc 0) k = signed_take_bit (n - Suc 0) l \ take_bit n k = take_bit n l" (is "?P \ ?Q") if "n > 0" proof - from that obtain m where m: "n = Suc m" by (cases n) auto show ?thesis proof assume ?Q have "take_bit (Suc m) (k + 2 ^ m) = take_bit (Suc m) (take_bit (Suc m) k + take_bit (Suc m) (2 ^ m))" by (simp only: take_bit_add) also have "\ = take_bit (Suc m) (take_bit (Suc m) l + take_bit (Suc m) (2 ^ m))" by (simp only: \?Q\ m [symmetric]) also have "\ = take_bit (Suc m) (l + 2 ^ m)" by (simp only: take_bit_add) finally show ?P by (simp only: signed_take_bit_eq_take_bit m) simp next assume ?P with that have "(k + 2 ^ (n - Suc 0)) mod 2 ^ n = (l + 2 ^ (n - Suc 0)) mod 2 ^ n" by (simp add: signed_take_bit_eq_take_bit' take_bit_eq_mod) then have "(i + (k + 2 ^ (n - Suc 0))) mod 2 ^ n = (i + (l + 2 ^ (n - Suc 0))) mod 2 ^ n" for i by (metis mod_add_eq) then have "k mod 2 ^ n = l mod 2 ^ n" by (metis add_diff_cancel_right' uminus_add_conv_diff) then show ?Q by (simp add: take_bit_eq_mod) qed qed subsection \Bit strings as quotient type\ subsubsection \Basic properties\ quotient_type (overloaded) 'a word = int / "\k l. take_bit LENGTH('a) k = take_bit LENGTH('a::len0) l" by (auto intro!: equivpI reflpI sympI transpI) instantiation word :: (len0) "{semiring_numeral, comm_semiring_0, comm_ring}" begin lift_definition zero_word :: "'a word" is 0 . lift_definition one_word :: "'a word" is 1 . lift_definition plus_word :: "'a word \ 'a word \ 'a word" is plus by (subst take_bit_add [symmetric]) (simp add: take_bit_add) lift_definition uminus_word :: "'a word \ 'a word" is uminus by (subst take_bit_uminus [symmetric]) (simp add: take_bit_uminus) lift_definition minus_word :: "'a word \ 'a word \ 'a word" is minus by (subst take_bit_minus [symmetric]) (simp add: take_bit_minus) lift_definition times_word :: "'a word \ 'a word \ 'a word" is times by (auto simp add: take_bit_eq_mod intro: mod_mult_cong) instance by standard (transfer; simp add: algebra_simps)+ end instance word :: (len) comm_ring_1 by standard (transfer; simp)+ quickcheck_generator word constructors: "zero_class.zero :: ('a::len0) word", "numeral :: num \ ('a::len0) word", "uminus :: ('a::len0) word \ ('a::len0) word" context includes lifting_syntax notes power_transfer [transfer_rule] begin lemma power_transfer_word [transfer_rule]: \(pcr_word ===> (=) ===> pcr_word) (^) (^)\ by transfer_prover end subsubsection \Conversions\ context includes lifting_syntax notes transfer_rule_of_bool [transfer_rule] transfer_rule_numeral [transfer_rule] transfer_rule_of_nat [transfer_rule] transfer_rule_of_int [transfer_rule] begin lemma [transfer_rule]: "((=) ===> (pcr_word :: int \ 'a::len word \ bool)) of_bool of_bool" by transfer_prover lemma [transfer_rule]: "((=) ===> (pcr_word :: int \ 'a::len word \ bool)) numeral numeral" by transfer_prover lemma [transfer_rule]: "((=) ===> pcr_word) int of_nat" by transfer_prover lemma [transfer_rule]: "((=) ===> pcr_word) (\k. k) of_int" proof - have "((=) ===> pcr_word) of_int of_int" by transfer_prover then show ?thesis by (simp add: id_def) qed end lemma abs_word_eq: "abs_word = of_int" by (rule ext) (transfer, rule) context semiring_1 begin lift_definition unsigned :: "'b::len0 word \ 'a" is "of_nat \ nat \ take_bit LENGTH('b)" by simp lemma unsigned_0 [simp]: "unsigned 0 = 0" by transfer simp end context semiring_char_0 begin lemma word_eq_iff_unsigned: "a = b \ unsigned a = unsigned b" by safe (transfer; simp add: eq_nat_nat_iff) end instantiation word :: (len0) equal begin definition equal_word :: "'a word \ 'a word \ bool" where "equal_word a b \ (unsigned a :: int) = unsigned b" instance proof fix a b :: "'a word" show "HOL.equal a b \ a = b" using word_eq_iff_unsigned [of a b] by (auto simp add: equal_word_def) qed end context ring_1 begin lift_definition signed :: "'b::len word \ 'a" is "of_int \ signed_take_bit (LENGTH('b) - 1)" by (simp add: signed_take_bit_eq_iff_take_bit_eq [symmetric]) lemma signed_0 [simp]: "signed 0 = 0" by transfer simp end lemma unsigned_of_nat [simp]: "unsigned (of_nat n :: 'a word) = take_bit LENGTH('a::len) n" by transfer (simp add: nat_eq_iff take_bit_eq_mod zmod_int) lemma of_nat_unsigned [simp]: "of_nat (unsigned a) = a" by transfer simp lemma of_int_unsigned [simp]: "of_int (unsigned a) = a" by transfer simp lemma unsigned_nat_less: \unsigned a < (2 ^ LENGTH('a) :: nat)\ for a :: \'a::len0 word\ by transfer (simp add: take_bit_eq_mod) lemma unsigned_int_less: \unsigned a < (2 ^ LENGTH('a) :: int)\ for a :: \'a::len0 word\ by transfer (simp add: take_bit_eq_mod) context ring_char_0 begin lemma word_eq_iff_signed: "a = b \ signed a = signed b" by safe (transfer; auto simp add: signed_take_bit_eq_iff_take_bit_eq) end lemma signed_of_int [simp]: "signed (of_int k :: 'a word) = signed_take_bit (LENGTH('a::len) - 1) k" by transfer simp lemma of_int_signed [simp]: "of_int (signed a) = a" by transfer (simp add: signed_take_bit_eq_take_bit take_bit_eq_mod mod_simps) subsubsection \Properties\ lemma exp_eq_zero_iff: \(2 :: 'a::len word) ^ n = 0 \ LENGTH('a) \ n\ by transfer simp subsubsection \Division\ instantiation word :: (len0) modulo begin lift_definition divide_word :: "'a word \ 'a word \ 'a word" is "\a b. take_bit LENGTH('a) a div take_bit LENGTH('a) b" by simp lift_definition modulo_word :: "'a word \ 'a word \ 'a word" is "\a b. take_bit LENGTH('a) a mod take_bit LENGTH('a) b" by simp instance .. end lemma zero_word_div_eq [simp]: \0 div a = 0\ for a :: \'a::len0 word\ by transfer simp lemma div_zero_word_eq [simp]: \a div 0 = 0\ for a :: \'a::len0 word\ by transfer simp context includes lifting_syntax begin lemma [transfer_rule]: "(pcr_word ===> (\)) even ((dvd) 2 :: 'a::len word \ bool)" proof - have even_word_unfold: "even k \ (\l. take_bit LENGTH('a) k = take_bit LENGTH('a) (2 * l))" (is "?P \ ?Q") for k :: int proof assume ?P then show ?Q by auto next assume ?Q then obtain l where "take_bit LENGTH('a) k = take_bit LENGTH('a) (2 * l)" .. then have "even (take_bit LENGTH('a) k)" by simp then show ?P by simp qed show ?thesis by (simp only: even_word_unfold [abs_def] dvd_def [where ?'a = "'a word", abs_def]) transfer_prover qed end instance word :: (len) semiring_modulo proof show "a div b * b + a mod b = a" for a b :: "'a word" proof transfer fix k l :: int define r :: int where "r = 2 ^ LENGTH('a)" then have r: "take_bit LENGTH('a) k = k mod r" for k by (simp add: take_bit_eq_mod) have "k mod r = ((k mod r) div (l mod r) * (l mod r) + (k mod r) mod (l mod r)) mod r" by (simp add: div_mult_mod_eq) also have "... = (((k mod r) div (l mod r) * (l mod r)) mod r + (k mod r) mod (l mod r)) mod r" by (simp add: mod_add_left_eq) also have "... = (((k mod r) div (l mod r) * l) mod r + (k mod r) mod (l mod r)) mod r" by (simp add: mod_mult_right_eq) finally have "k mod r = ((k mod r) div (l mod r) * l + (k mod r) mod (l mod r)) mod r" by (simp add: mod_simps) with r show "take_bit LENGTH('a) (take_bit LENGTH('a) k div take_bit LENGTH('a) l * l + take_bit LENGTH('a) k mod take_bit LENGTH('a) l) = take_bit LENGTH('a) k" by simp qed qed instance word :: (len) semiring_parity proof show "\ 2 dvd (1::'a word)" by transfer simp show even_iff_mod_2_eq_0: "2 dvd a \ a mod 2 = 0" for a :: "'a word" by transfer (simp_all add: mod_2_eq_odd) show "\ 2 dvd a \ a mod 2 = 1" for a :: "'a word" by transfer (simp_all add: mod_2_eq_odd) qed subsubsection \Orderings\ instantiation word :: (len0) linorder begin lift_definition less_eq_word :: "'a word \ 'a word \ bool" is "\a b. take_bit LENGTH('a) a \ take_bit LENGTH('a) b" by simp lift_definition less_word :: "'a word \ 'a word \ bool" is "\a b. take_bit LENGTH('a) a < take_bit LENGTH('a) b" by simp instance by standard (transfer; auto)+ end context linordered_semidom begin lemma word_less_eq_iff_unsigned: "a \ b \ unsigned a \ unsigned b" by (transfer fixing: less_eq) (simp add: nat_le_eq_zle) lemma word_less_iff_unsigned: "a < b \ unsigned a < unsigned b" by (transfer fixing: less) (auto dest: preorder_class.le_less_trans [OF take_bit_nonnegative]) end lemma word_greater_zero_iff: \a > 0 \ a \ 0\ for a :: \'a::len0 word\ by transfer (simp add: less_le) lemma of_nat_word_eq_iff: \of_nat m = (of_nat n :: 'a::len word) \ take_bit LENGTH('a) m = take_bit LENGTH('a) n\ by transfer (simp add: take_bit_of_nat) lemma of_nat_word_less_eq_iff: \of_nat m \ (of_nat n :: 'a::len word) \ take_bit LENGTH('a) m \ take_bit LENGTH('a) n\ by transfer (simp add: take_bit_of_nat) lemma of_nat_word_less_iff: \of_nat m < (of_nat n :: 'a::len word) \ take_bit LENGTH('a) m < take_bit LENGTH('a) n\ by transfer (simp add: take_bit_of_nat) lemma of_nat_word_eq_0_iff: \of_nat n = (0 :: 'a::len word) \ 2 ^ LENGTH('a) dvd n\ using of_nat_word_eq_iff [where ?'a = 'a, of n 0] by (simp add: take_bit_eq_0_iff) lemma of_int_word_eq_iff: \of_int k = (of_int l :: 'a::len word) \ take_bit LENGTH('a) k = take_bit LENGTH('a) l\ by transfer rule lemma of_int_word_less_eq_iff: \of_int k \ (of_int l :: 'a::len word) \ take_bit LENGTH('a) k \ take_bit LENGTH('a) l\ by transfer rule lemma of_int_word_less_iff: \of_int k < (of_int l :: 'a::len word) \ take_bit LENGTH('a) k < take_bit LENGTH('a) l\ by transfer rule lemma of_int_word_eq_0_iff: \of_int k = (0 :: 'a::len word) \ 2 ^ LENGTH('a) dvd k\ using of_int_word_eq_iff [where ?'a = 'a, of k 0] by (simp add: take_bit_eq_0_iff) subsection \Bit structure on \<^typ>\'a word\\ lemma word_bit_induct [case_names zero even odd]: \P a\ if word_zero: \P 0\ and word_even: \\a. P a \ 0 < a \ a < 2 ^ (LENGTH('a) - 1) \ P (2 * a)\ and word_odd: \\a. P a \ a < 2 ^ (LENGTH('a) - 1) \ P (1 + 2 * a)\ for P and a :: \'a::len word\ proof - define m :: nat where \m = LENGTH('a) - 1\ then have l: \LENGTH('a) = Suc m\ by simp define n :: nat where \n = unsigned a\ then have \n < 2 ^ LENGTH('a)\ by (simp add: unsigned_nat_less) then have \n < 2 * 2 ^ m\ by (simp add: l) then have \P (of_nat n)\ proof (induction n rule: nat_bit_induct) case zero show ?case by simp (rule word_zero) next case (even n) then have \n < 2 ^ m\ by simp with even.IH have \P (of_nat n)\ by simp moreover from \n < 2 ^ m\ even.hyps have \0 < (of_nat n :: 'a word)\ by (auto simp add: word_greater_zero_iff of_nat_word_eq_0_iff l) moreover from \n < 2 ^ m\ have \(of_nat n :: 'a word) < 2 ^ (LENGTH('a) - 1)\ using of_nat_word_less_iff [where ?'a = 'a, of n \2 ^ m\] by (cases \m = 0\) (simp_all add: not_less take_bit_eq_self ac_simps l) ultimately have \P (2 * of_nat n)\ by (rule word_even) then show ?case by simp next case (odd n) then have \Suc n \ 2 ^ m\ by simp with odd.IH have \P (of_nat n)\ by simp moreover from \Suc n \ 2 ^ m\ have \(of_nat n :: 'a word) < 2 ^ (LENGTH('a) - 1)\ using of_nat_word_less_iff [where ?'a = 'a, of n \2 ^ m\] by (cases \m = 0\) (simp_all add: not_less take_bit_eq_self ac_simps l) ultimately have \P (1 + 2 * of_nat n)\ by (rule word_odd) then show ?case by simp qed then show ?thesis by (simp add: n_def) qed lemma bit_word_half_eq: \(of_bool b + a * 2) div 2 = a\ if \a < 2 ^ (LENGTH('a) - Suc 0)\ for a :: \'a::len word\ proof (cases \2 \ LENGTH('a::len)\) case False have \of_bool (odd k) < (1 :: int) \ even k\ for k :: int by auto with False that show ?thesis by (auto; transfer) simp_all next case True obtain n where length: \LENGTH('a) = Suc n\ by (cases \LENGTH('a)\) simp_all show ?thesis proof (cases b) case False moreover have \a * 2 div 2 = a\ using that proof transfer fix k :: int from length have \k * 2 mod 2 ^ LENGTH('a) = (k mod 2 ^ n) * 2\ by simp moreover assume \take_bit LENGTH('a) k < take_bit LENGTH('a) (2 ^ (LENGTH('a) - Suc 0))\ with \LENGTH('a) = Suc n\ have \k mod 2 ^ LENGTH('a) = k mod 2 ^ n\ by (simp add: take_bit_eq_mod divmod_digit_0) ultimately have \take_bit LENGTH('a) (k * 2) = take_bit LENGTH('a) k * 2\ by (simp add: take_bit_eq_mod) with True show \take_bit LENGTH('a) (take_bit LENGTH('a) (k * 2) div take_bit LENGTH('a) 2) = take_bit LENGTH('a) k\ by simp qed ultimately show ?thesis by simp next case True moreover have \(1 + a * 2) div 2 = a\ using that proof transfer fix k :: int from length have \(1 + k * 2) mod 2 ^ LENGTH('a) = 1 + (k mod 2 ^ n) * 2\ using pos_zmod_mult_2 [of \2 ^ n\ k] by (simp add: ac_simps) moreover assume \take_bit LENGTH('a) k < take_bit LENGTH('a) (2 ^ (LENGTH('a) - Suc 0))\ with \LENGTH('a) = Suc n\ have \k mod 2 ^ LENGTH('a) = k mod 2 ^ n\ by (simp add: take_bit_eq_mod divmod_digit_0) ultimately have \take_bit LENGTH('a) (1 + k * 2) = 1 + take_bit LENGTH('a) k * 2\ by (simp add: take_bit_eq_mod) with True show \take_bit LENGTH('a) (take_bit LENGTH('a) (1 + k * 2) div take_bit LENGTH('a) 2) = take_bit LENGTH('a) k\ by auto qed ultimately show ?thesis by simp qed qed lemma even_mult_exp_div_word_iff: \even (a * 2 ^ m div 2 ^ n) \ \ ( m \ n \ n < LENGTH('a) \ odd (a div 2 ^ (n - m)))\ for a :: \'a::len word\ by transfer (auto simp flip: drop_bit_eq_div simp add: even_drop_bit_iff_not_bit bit_take_bit_iff, - simp_all flip: push_bit_eq_mult add: bit_push_bit_eq_int) + simp_all flip: push_bit_eq_mult add: bit_push_bit_iff_int) -(*lemma even_range_div_iff_word: +(*lemma even_mask_div_iff_word: \even ((2 ^ m - 1) div (2::'a word) ^ n) \ 2 ^ n = (0::'a::len word) \ m \ n\ - by transfer (auto simp add: take_bit_of_range even_range_div_iff)*) + by transfer (auto simp add: take_bit_of_mask even_mask_div_iff)*) instance word :: (len) semiring_bits proof show \P a\ if stable: \\a. a div 2 = a \ P a\ and rec: \\a b. P a \ (of_bool b + 2 * a) div 2 = a \ P (of_bool b + 2 * a)\ for P and a :: \'a word\ proof (induction a rule: word_bit_induct) case zero from stable [of 0] show ?case by simp next case (even a) with rec [of a False] show ?case using bit_word_half_eq [of a False] by (simp add: ac_simps) next case (odd a) with rec [of a True] show ?case using bit_word_half_eq [of a True] by (simp add: ac_simps) qed show \0 div a = 0\ for a :: \'a word\ by transfer simp show \a div 1 = a\ for a :: \'a word\ by transfer simp show \a mod b div b = 0\ for a b :: \'a word\ apply transfer apply (simp add: take_bit_eq_mod) apply (subst (3) mod_pos_pos_trivial [of _ \2 ^ LENGTH('a)\]) apply simp_all apply (metis le_less mod_by_0 pos_mod_conj zero_less_numeral zero_less_power) using pos_mod_bound [of \2 ^ LENGTH('a)\] apply simp proof - fix aa :: int and ba :: int have f1: "\i n. (i::int) mod 2 ^ n = 0 \ 0 < i mod 2 ^ n" by (metis le_less take_bit_eq_mod take_bit_nonnegative) have "(0::int) < 2 ^ len_of (TYPE('a)::'a itself) \ ba mod 2 ^ len_of (TYPE('a)::'a itself) \ 0 \ aa mod 2 ^ len_of (TYPE('a)::'a itself) mod (ba mod 2 ^ len_of (TYPE('a)::'a itself)) < 2 ^ len_of (TYPE('a)::'a itself)" by (metis (no_types) mod_by_0 unique_euclidean_semiring_numeral_class.pos_mod_bound zero_less_numeral zero_less_power) then show "aa mod 2 ^ len_of (TYPE('a)::'a itself) mod (ba mod 2 ^ len_of (TYPE('a)::'a itself)) < 2 ^ len_of (TYPE('a)::'a itself)" using f1 by (meson le_less less_le_trans unique_euclidean_semiring_numeral_class.pos_mod_bound) qed show \(1 + a) div 2 = a div 2\ if \even a\ for a :: \'a word\ using that by transfer (auto dest: le_Suc_ex) show \(2 :: 'a word) ^ m div 2 ^ n = of_bool ((2 :: 'a word) ^ m \ 0 \ n \ m) * 2 ^ (m - n)\ for m n :: nat by transfer (simp, simp add: exp_div_exp_eq) show "a div 2 ^ m div 2 ^ n = a div 2 ^ (m + n)" for a :: "'a word" and m n :: nat apply transfer apply (auto simp add: not_less take_bit_drop_bit ac_simps simp flip: drop_bit_eq_div) apply (simp add: drop_bit_take_bit) done show "a mod 2 ^ m mod 2 ^ n = a mod 2 ^ min m n" for a :: "'a word" and m n :: nat by transfer (auto simp flip: take_bit_eq_mod simp add: ac_simps) show \a * 2 ^ m mod 2 ^ n = a mod 2 ^ (n - m) * 2 ^ m\ if \m \ n\ for a :: "'a word" and m n :: nat using that apply transfer apply (auto simp flip: take_bit_eq_mod) apply (auto simp flip: push_bit_eq_mult simp add: push_bit_take_bit split: split_min_lin) done show \a div 2 ^ n mod 2 ^ m = a mod (2 ^ (n + m)) div 2 ^ n\ for a :: "'a word" and m n :: nat by transfer (auto simp add: not_less take_bit_drop_bit ac_simps simp flip: take_bit_eq_mod drop_bit_eq_div split: split_min_lin) qed context includes lifting_syntax begin lemma transfer_rule_bit_word [transfer_rule]: \((pcr_word :: int \ 'a::len word \ bool) ===> (=)) (\k n. n < LENGTH('a) \ bit k n) bit\ proof - let ?t = \\a n. odd (take_bit LENGTH('a) a div take_bit LENGTH('a) ((2::int) ^ n))\ have \((pcr_word :: int \ 'a word \ bool) ===> (=)) ?t bit\ by (unfold bit_def) transfer_prover also have \?t = (\k n. n < LENGTH('a) \ bit k n)\ by (simp add: fun_eq_iff bit_take_bit_iff flip: bit_def) finally show ?thesis . qed end instantiation word :: (len) semiring_bit_shifts begin lift_definition push_bit_word :: \nat \ 'a word \ 'a word\ is push_bit proof - show \take_bit LENGTH('a) (push_bit n k) = take_bit LENGTH('a) (push_bit n l)\ if \take_bit LENGTH('a) k = take_bit LENGTH('a) l\ for k l :: int and n :: nat proof - from that have \take_bit (LENGTH('a) - n) (take_bit LENGTH('a) k) = take_bit (LENGTH('a) - n) (take_bit LENGTH('a) l)\ by simp moreover have \min (LENGTH('a) - n) LENGTH('a) = LENGTH('a) - n\ by simp ultimately show ?thesis by (simp add: take_bit_push_bit) qed qed lift_definition drop_bit_word :: \nat \ 'a word \ 'a word\ is \\n. drop_bit n \ take_bit LENGTH('a)\ by (simp add: take_bit_eq_mod) instance proof show \push_bit n a = a * 2 ^ n\ for n :: nat and a :: "'a word" by transfer (simp add: push_bit_eq_mult) show \drop_bit n a = a div 2 ^ n\ for n :: nat and a :: "'a word" by transfer (simp flip: drop_bit_eq_div add: drop_bit_take_bit) qed end instantiation word :: (len) ring_bit_operations begin lift_definition not_word :: "'a word \ 'a word" is not by (simp add: take_bit_not_iff_int) lift_definition and_word :: "'a word \ 'a word \ 'a word" is \and\ by simp lift_definition or_word :: "'a word \ 'a word \ 'a word" is or by simp lift_definition xor_word :: "'a word \ 'a word \ 'a word" is xor by simp instance proof fix a b :: \'a word\ and n :: nat show \- a = NOT (a - 1)\ by transfer (simp add: minus_eq_not_minus_1) show \bit (NOT a) n \ (2 :: 'a word) ^ n \ 0 \ \ bit a n\ by transfer (simp add: bit_not_iff) show \bit (a AND b) n \ bit a n \ bit b n\ by transfer (auto simp add: bit_and_iff) show \bit (a OR b) n \ bit a n \ bit b n\ by transfer (auto simp add: bit_or_iff) show \bit (a XOR b) n \ bit a n \ bit b n\ by transfer (auto simp add: bit_xor_iff) qed end end